Mathbench

Chapter 1 — Integrating Essential Skills

This chapter is a fifth of the whole test — nine questions out of forty-five, more than Statistics and Number & Quantity put together. It is also the category almost every ACT book treats as a warm-up, because its mathematics is the easiest thing on the paper: rates, percentages, ratios, averages, area.

That combination — a large share of the marks, and material you have met before — is why this chapter comes first. It is the most improvable part of the ACT. The questions are not hard; they are fiddly, and they are placed early in the paper where you are still settling down. Nearly every mark lost here is lost to one of four things:

Every wrong option in this chapter is one of those four, named.

A note about the calculator. You may use one on every ACT question. That means the arithmetic is not what is being examined — the setup is. A calculator will give you a beautifully precise answer to the wrong equation.

Topics covered: rates and unit conversion · percentages · percentage change · ratios and proportion · area, perimeter and volume in context · averages and medians · expressing numbers in different ways


Section 1 — Rates and Unit Conversion

A rate compares two quantities with different units: miles per hour, pages per minute, dollars per kilogram. The word "per" means divided by.

The whole skill is keeping track of which unit is on top. Write the rate as a fraction with its units attached, and arrange the multiplication so the units you do not want cancel:

30  mileshour×1 hour60 minutes=12  milesminute30 \; \frac{\text{miles}}{\text{hour}} \times \frac{1 \text{ hour}}{60 \text{ minutes}} = \frac{1}{2} \; \frac{\text{miles}}{\text{minute}}

If you set it up and the wrong unit survives, you have multiplied where you should have divided. That check costs two seconds and catches almost every conversion error.


Q1Basic

Topic: A unit rate over a longer period

An office printer runs at a steady rate, producing 3 pages every 4 seconds without pausing between jobs. How many pages does the printer produce in one minute?

A) 1212

B) 4545

C) 8080

D) 180180

Show the worked solution

Answer: B

Explanation

The rate is 3 pages per 4 seconds, so per second it is

34=0.75 pages per second\frac{3}{4} = 0.75 \text{ pages per second}

One minute is 60 seconds, so

0.75×60=450.75 \times 60 = 45

Check the units: pagessecond×seconds\dfrac{\text{pages}}{\text{second}} \times \text{seconds} leaves pages. Correct.

Why each wrong option is wrong:

  • A, 1212 — multiplied 3 by 4. Those are the two halves of one rate, not two quantities to combine.
  • C, 8080 — used 43\frac{4}{3} instead of 34,\frac{3}{4}\mathclose{,} that is, 4 pages per 3 seconds. Turning a rate upside down is the most common slip in this topic. Ask yourself which number is bigger and whether the answer should be.
  • D, 180180 — read the rate as 3 pages per second and ignored the 4.

Takeaway: write the rate as a fraction with units attached, then multiply so the unwanted unit cancels. If the surviving unit is wrong, so is the arithmetic.


Q2Medium

Topic: Converting a rate between two pairs of units

A boat is travelling at a steady 30 miles per hour. One mile is 5280 feet and one hour is 3600 seconds. What is the boat's speed in feet per second?

F) 158400158400

G) 26402640

H) 8888

J) 4444

Show the worked solution

Answer: J

Explanation

Change both units in one chain, and let them cancel:

30  mileshour×5280 feet1 mile×1 hour3600 seconds30 \; \frac{\text{miles}}{\text{hour}} \times \frac{5280 \text{ feet}}{1 \text{ mile}} \times \frac{1 \text{ hour}}{3600 \text{ seconds}}

Miles cancel against miles, hours against hours, and feet over seconds survives — which is what was asked for.

30×52803600=1584003600=44\frac{30 \times 5280}{3600} = \frac{158400}{3600} = 44

A sanity check worth remembering: 60 mph is 88 feet per second. So 30 mph should be half of that, 44. It is.

Why each wrong option is wrong:

  • F, 158400158400 — changed the miles into feet and left the hours alone. That is feet per hour.
  • G, 26402640 — converted correctly to feet per minute and stopped there.
  • H, 8888 — the speed for 60 miles per hour. Worth remembering, but this boat is doing half of that.

Takeaway: when both units change, write both conversions as fractions in one line and cancel. And keep "60 mph = 88 ft/s" in your head as a check.


Q3Medium

Topic: A rate with a fixed charge on top

A plumber charges a fixed call-out fee of $45 for turning up, and then $30 for each hour spent on the job. One repair was invoiced at $180 in total. How many hours did the repair take?

A) 4.54.5

B) 66

C) 7.57.5

D) 135135

Show the worked solution

Answer: A

Explanation

Let hh be the number of hours. The bill is the fixed part plus the hourly part:

45+30h=18045 + 30h = 180

Take the call-out fee off first, because it is charged once and is not part of the rate:

30h=13530h = 135

h=13530=4.5 hoursh = \frac{135}{30} = 4.5 \text{ hours}

Check: 30×4.5=135,30 \times 4.5 = 135\mathclose{,} and 135+45=180.135 + 45 = 180\mathclose{.} Correct.

Why each wrong option is wrong:

  • B, 66 — divided the whole bill by the hourly rate, as though there were no call-out fee. This is the trap the question is built around.
  • C, 7.57.5 — added the call-out fee instead of subtracting it.
  • D, 135135 — took the fee off correctly and stopped. 135 is the labour charge in dollars, not a number of hours.

Takeaway: a fixed charge is not part of the rate. Remove it before you divide, never after.


Q4Medium

Topic: Comparing two rates to find better value

A shop sells the same coffee in two sizes. A 250 gram bag costs $5 and a 450 gram bag costs $7.50. How many more grams per dollar does the better-value size give?

F) 200200

G) 6060

H) 5050

J) 1010

Show the worked solution

Answer: J

Explanation

"Value" here means grams per dollar, so divide grams by dollars for each:

250 g bag: 2505=50 g per dollar\text{250 g bag: } \frac{250}{5} = 50 \text{ g per dollar}

450 g bag: 4507.5=60 g per dollar\text{450 g bag: } \frac{450}{7.5} = 60 \text{ g per dollar}

The larger bag is better value. The question asks for the difference:

60−50=10 g per dollar60 - 50 = 10 \text{ g per dollar}

Why each wrong option is wrong:

  • F, 200200 — compared the weights, 450−250,450 - 250\mathclose{,} ignoring price altogether.
  • H, 5050 and G, 6060 — each gives one bag's rate rather than the difference between them. Both are steps on the way; neither is the answer.

Takeaway: "better value" always means a rate, never a raw size or a raw price. And read the last line: this question wanted the difference, not the winner.


Q5Medium

Topic: Converting a volume before using a rate

A concentrate is mixed at a rate of 2 scoops for every 4 cups of water, and a technician has 5 gallons of water to use up. There are 16 cups in a gallon. How many scoops of concentrate are needed?

A) 4040

B) 2020

C) 1010

D) 2.52.5

Show the worked solution

Answer: A

Explanation

Convert first:

5 gallons×16cupsgallon=80 cups5 \text{ gallons} \times 16 \frac{\text{cups}}{\text{gallon}} = 80 \text{ cups}

The rate is 2 scoops per 4 cups, which is 24=12\frac{2}{4} = \frac{1}{2} scoop per cup:

80×12=40 scoops80 \times \frac{1}{2} = 40 \text{ scoops}

Why each wrong option is wrong:

  • B, 2020 — divided by 4 but never multiplied by the 2.
  • C, 1010 — divided the 80 cups by 4 and then by the 2 as well. The 2 scoops multiply.
  • D, 2.52.5 — applied the rate to 5 gallons without converting to cups. The unit check catches this instantly: the answer would be in scoops per gallon, not scoops.

Takeaway: convert to a common unit before applying a rate, not after.


Q6Hard

Topic: A two-step conversion of a rate

A storage tank has developed a steady leak and is losing 3 litres every minute. What is the rate of loss in litres per day?

F) 7272

G) 180180

H) 14401440

J) 43204320

Show the worked solution

Answer: J

Explanation

Go one step at a time, and never skip a unit:

3litresminute×60minuteshour=180litreshour3 \frac{\text{litres}}{\text{minute}} \times 60 \frac{\text{minutes}}{\text{hour}} = 180 \frac{\text{litres}}{\text{hour}}

180litreshour×24hoursday=4320litresday180 \frac{\text{litres}}{\text{hour}} \times 24 \frac{\text{hours}}{\text{day}} = 4320 \frac{\text{litres}}{\text{day}}

Why each wrong option is wrong:

  • F, 7272 — jumped from minutes straight to days by multiplying by 24, which skips the factor of 60.
  • G, 180180 — stopped after the first conversion, giving litres per hour. Stopping one step early is the single most common error in this whole chapter.
  • H, 14401440 — the number of minutes in a day. The 3 litres a minute were never applied.

Takeaway: do multi-step conversions one unit at a time and write each one down. The two failure modes are stopping early and going one step too far, and both are invisible unless the units are on the page.


Q7Medium

Topic: Distance, speed and time in a single journey

A cyclist rides for 40 minutes at a steady 18 kilometres per hour. How far, in kilometres, does the cyclist travel?

A) 0.450.45

B) 1212

C) 2727

D) 720720

Show the worked solution

Answer: B

Explanation

Distance is speed multiplied by time, but only when the units agree. The speed is per hour, so convert 40 minutes to hours:

40 minutes=4060=23 hour40 \text{ minutes} = \frac{40}{60} = \frac{2}{3} \text{ hour}

18×23=12 km18 \times \frac{2}{3} = 12 \text{ km}

A quick sanity check: in a full hour the cyclist would do 18 km, and 40 minutes is two thirds of an hour, so the answer must be less than 18. It is.

Why each wrong option is wrong:

  • A, 0.450.45 — divided instead of multiplying.
  • C, 2727 — used 6040\frac{60}{40} instead of 4060,\frac{40}{60}\mathclose{,} turning the time fraction upside down, which makes the answer bigger than 18.
  • D, 720720 — multiplied 18 by 40 directly, mixing hours with minutes. The result, 720 km in 40 minutes, fails the sanity check by a mile.

Takeaway: before multiplying a speed by a time, check they use the same unit of time. Then check the answer is on the right side of "one whole hour".


Q8Hard

Topic: Two rates working together

One pump can empty a tank in 6 hours and a second pump can empty the same tank in 12 hours. Both are switched on at the same time and run together until the tank is empty. How many hours does it take the two pumps working together?

F) 44

G) 99

H) 1818

J) 7272

Show the worked solution

Answer: F

Explanation

The mistake this question exists to catch is adding the times. Times do not add — think about it: two pumps together must be faster than either alone, so the answer has to be less than 6. That single check eliminates three of the four options before any arithmetic.

What does add is the rates. In one hour:

pump 1 empties 16 of the tankpump 2 empties 112\text{pump 1 empties } \frac{1}{6} \text{ of the tank} \qquad \text{pump 2 empties } \frac{1}{12}

16+112=212+112=312=14\frac{1}{6} + \frac{1}{12} = \frac{2}{12} + \frac{1}{12} = \frac{3}{12} = \frac{1}{4}

Together they empty a quarter of the tank per hour, so the whole tank takes

1÷14=4 hours1 \div \frac{1}{4} = 4 \text{ hours}

Why each wrong option is wrong:

  • G, 99 — averaged the two times, which is the same error in disguise: the answer is still not less than 6.
  • H, 1818 — added the two times. Two pumps cannot be slower than one.
  • J, 7272 — multiplied the times.

Takeaway: for combined-work questions, add the rates (1t),(\frac{1}{t})\mathclose{,} then invert at the end. And check the answer is smaller than the fastest worker alone — it always must be.


Section 2 — Percentages

A percentage is a fraction with 100 on the bottom. "17%" means 17100,\frac{17}{100}\mathclose{,} or 0.17.0.17\mathclose{.} Every percentage question on the ACT is one of four shapes:

the question what to do
what is p%p\% of N?N\mathclose{?} multiply: N×p100N \times \frac{p}{100}
AA is what percent of N?N\mathclose{?} divide, then multiply by 100: AN×100\frac{A}{N} \times 100
increase NN by p%p\% multiply by (1+p100)\left(1 + \frac{p}{100}\right)
decrease NN by p%p\% multiply by (1−p100)\left(1 - \frac{p}{100}\right)

The two rows that cost marks are the last two. Increasing by 15% is multiplying by 1.15, in one step — not "find 15%, then add it", which is the same thing but twice as many chances to slip. And the reverse of increasing by 15% is dividing by 1.15, not decreasing by 15%.


Q9Basic

Topic: A percentage increase

A jacket in a shop is priced at $80. At the start of the new season the shop raises the price of everything in that range by 15%, calculated on the current price. What is the new price of the jacket?

A) 9292

B) 81.281.2

C) 6868

D) 1212

Show the worked solution

Answer: A

Explanation

Increasing by 15% means multiplying by 1.15:1.15\mathclose{:}

80×1.15=9280 \times 1.15 = 92

If you would rather do it in two steps: 15% of 80 is 80×0.15=12,80 \times 0.15 = 12\mathclose{,} and 80+12=92.80 + 12 = 92\mathclose{.} Same answer, more steps, more chances to go wrong.

Why each wrong option is wrong:

  • B, 81.281.2 — added 1.5%, not 15%: the decimal point is one place out. A rise of 15% on 80 has to be more than 8.
  • C, 6868 — subtracted the 15% instead of adding it.
  • D, 1212 — gave the increase itself, 12,12\mathclose{,} and stopped. The question asked for the new price.

Takeaway: increase by p%p\% in one multiplication, by (1+p100).\left(1 + \frac{p}{100}\right)\mathclose{.} Then check you answered the question that was asked — the increase, or the new total?


Q10Medium

Topic: Working backwards from a percentage

A coat is offered in a sale at 20% off its original price, and after the reduction a customer pays $96 for it. What was the original price?

F) 7676

G) 115.2115.2

H) 116116

J) 120120

Show the worked solution

Answer: J

Explanation

After a 20% reduction the customer pays 80% of the original. Call the original price P:P\mathclose{:}

0.80×P=960.80 \times P = 96

P=960.80=120P = \frac{96}{0.80} = 120

Check: 20% of 120 is 24, and 120−24=96.120 - 24 = 96\mathclose{.} Correct.

The trap here is worth dwelling on. Adding 20% back onto 96 gives 96×1.2=115.20,96 \times 1.2 = 115.20\mathclose{,} not 120. Taking 20% off and then putting 20% back on does not return you to where you started, because the second percentage is taken from a smaller number. To undo a multiplication, you divide.

Why each wrong option is wrong:

  • G, 115.2115.2 — added 20% back on instead of dividing by 0.80. This is the intended trap, and it is very close to right.
  • H, 116116 and F, 7676 — treated the 20% as 20 dollars.

Takeaway: to undo a percentage change, divide by the multiplier. Off by 20% means divide by 0.8; up by 20% means divide by 1.2.


Q11Hard

Topic: Two percentage changes one after the other

A share price rises by 25% during one year and then falls by 20% during the next, each change being calculated on the price at the start of that year rather than on the original price. Over the two years taken together, the price has:

A) risen by 5%

B) returned to exactly its original value

C) fallen by 5%

D) risen by 45%

Show the worked solution

Answer: B

Explanation

Percentages do not add. Each change is a multiplication, so two changes one after the other multiply together.

Take a convenient starting price of 100:

100×1.25=125then125×0.80=100100 \times 1.25 = 125 \qquad \text{then} \qquad 125 \times 0.80 = 100

Back exactly where it started. In one line:

1.25×0.80=1.001.25 \times 0.80 = 1.00

A multiplier of exactly 1 means no overall change.

The reason it works out so neatly: a 20% fall undoes a 25% rise because 11.25=0.8.\frac{1}{1.25} = 0.8\mathclose{.} They are inverses.

Why each wrong option is wrong:

  • A, risen by 5% and C, fallen by 5% — subtracted the percentages, in one direction or the other. 25−2025 - 20 is not how successive changes combine.
  • D, risen by 45% — added them.

Takeaway: successive percentage changes multiply. Start from 100, apply each multiplier in turn, and read the answer off directly.


Q12Medium

Topic: A percentage of a percentage

In a town, 60% of the residents own a bicycle, and of those bicycle owners, 25% ride one every day. What percent of all residents ride every day?

F) 1515

G) 2525

H) 3535

J) 8585

Show the worked solution

Answer: F

Explanation

"Of those bicycle owners" is the key phrase: the 25% applies to the 60%, not to the town.

Take a town of 100 people:

bicycle owners=60daily riders=25% of 60=15\text{bicycle owners} = 60 \qquad \text{daily riders} = 25\% \text{ of } 60 = 15

15 out of 100 is 15%.

In one line, "of" means multiply:

0.60×0.25=0.15=15%0.60 \times 0.25 = 0.15 = 15\%

Why each wrong option is wrong:

  • G, 2525 — applied the 25% to the whole town, ignoring the fact that only bicycle owners were being described.
  • H, 3535 — subtracted them.
  • J, 8585 — added the percentages.

Takeaway: in percentage questions the word "of" means multiply. A percentage of a percentage is always smaller than either one.


Q13Medium

Topic: Cost, profit and selling price

A shop buys a chair from its supplier for $60 and sells it at a 35% profit calculated on that cost. What is the selling price?

A) 2121

B) 3939

C) 8181

D) 9595

Show the worked solution

Answer: C

Explanation

A 35% profit on the cost means the selling price is 135% of the cost:

60×1.35=8160 \times 1.35 = 81

In two steps: 35% of 60 is 60×0.35=21,60 \times 0.35 = 21\mathclose{,} and 60+21=81.60 + 21 = 81\mathclose{.}

Why each wrong option is wrong:

  • A, 2121 — gave the profit, 21,21\mathclose{,} not the selling price.
  • B, 3939 — subtracted the profit, which would be selling at a loss.
  • D, 9595 — added 35 dollars rather than 35 percent.

Takeaway: profit "on cost" means multiply the cost by (1+profit %100).\left(1 + \frac{\text{profit }\%}{100}\right)\mathclose{.} Then read the last line again: profit, or selling price?


Q14Basic

Topic: Expressing one number as a percentage of another

In a batch of 250 items, 40 were set aside for inspection. What percent of the batch was set aside?

F) 1616

G) 4040

H) 8484

J) 625625

Show the worked solution

Answer: F

Explanation

"What percent of 250" tells you 250 is the whole, so it goes on the bottom:

40250×100=16%\frac{40}{250} \times 100 = 16\%

Check it the other way: 16% of 250 is 250×0.16=40.250 \times 0.16 = 40\mathclose{.} Correct.

Why each wrong option is wrong:

  • G, 4040 — repeated the 40 with a percent sign attached.
  • H, 8484 — gave the percentage that was not set aside.
  • J, 625625 — divided 250 by 40, giving 625%. A part cannot be more than 100% of its whole, so this fails an instant sanity check.

Takeaway: the number after "percent of" is the whole and goes underneath. If your answer is over 100%, you have divided upside down.


Q15Hard

Topic: Two successive discounts as a single one

A shop reduces a coat by 20%, and then takes a further 10% off the already reduced price at the till. What single percentage reduction off the original price is this pair of discounts equivalent to?

A) 7272

B) 3030

C) 2828

D) 22

Show the worked solution

Answer: C

Explanation

Discounts do not add, because the second is taken from the reduced price.

Start from 100. After 20% off you pay 80% of it; after a further 10% off you pay 90% of that:

100×0.80×0.90=72100 \times 0.80 \times 0.90 = 72

So the customer pays 72% of the original, which means the reduction is

100−72=28%100 - 72 = 28\%

Why each wrong option is wrong:

  • B, 3030 — added the two discounts. If that were right, ten successive 10% discounts would make everything free.
  • A, 7272 — gave the percentage paid, not the percentage taken off. A very near miss, and the reason the last line of the question says "reduction".
  • D, 22 — multiplied 20 by 10 and divided by 100.

Takeaway: chain the multipliers, then subtract from 100 if the question asks for the discount rather than the price.


Q16Hard

Topic: A repeated fixed rise, not a percentage rise

Tanya earned $34000 in her first year in a job, and in each following year her salary went up by the same number of dollars as it had the year before. By her fourth year she was earning $43000. What was her salary in the second year?

F) 3625036250

G) 3700037000

H) 4000040000

J) 4300043000

Show the worked solution

Answer: G

Explanation

The same dollar amount each year, not the same percentage — so this is addition, not multiplication.

From year 1 to year 4 there are three rises, not four. That off-by-one is the whole question:

43000−34000=9000 over three rises43000 - 34000 = 9000 \text{ over three rises}

each rise=90003=3000\text{each rise} = \frac{9000}{3} = 3000

So year 2 is 34000+3000=37000.34000 + 3000 = 37000\mathclose{.}

Check the whole run: 34000, 37000, 40000, 43000. Four years, three steps. Correct.

Why each wrong option is wrong:

  • F, 3625036250 — divided the 9000 by four instead of three: one for each year rather than one for each rise. This is the error the question is built around, and it is very easy to make quickly.
  • H, 4000040000 — subtracted one rise from the fourth year, which gives year 3.
  • J, 4300043000 — added the entire 9000 in one go.

Takeaway: between year 1 and year nn there are n−1n - 1 steps. Count the gaps, not the years. Write the whole sequence out if there is any doubt — it takes five seconds and removes the error entirely.


Section 3 — Ratios and Proportion

A ratio compares parts of the same whole. "The ratio of red to blue is 4 : 74 : 7" does not mean 4 red and 7 blue; it means that for every 4 red there are 7 blue, in some multiple.

The reliable method is the multiplier. Write the ratio as parts, add them to get the total number of parts, and find what one part is worth:

4 : 7⟶4+7=11 parts4 : 7 \quad\longrightarrow\quad 4 + 7 = 11 \text{ parts}

If there are 44 objects altogether, one part is 44÷11=4,44 \div 11 = 4\mathclose{,} so red is 4×4=164 \times 4 = 16 and blue is 7×4=28.7 \times 4 = 28\mathclose{.}

The single most common error is using 4 out of 7 instead of 4 out of 11 — confusing a part-to-part ratio with a part-to-whole fraction.


Q17Basic

Topic: Part-to-whole from a part-to-part ratio

A bag contains only red and blue marbles, and the ratio of red to blue is 4:7.4: 7\mathclose{.} There are 44 marbles altogether. How many marbles are red?

A) 44

B) 1111

C) 1616

D) 2828

Show the worked solution

Answer: C

Explanation

Add the parts to find how many the whole is divided into:

4+7=11 parts4 + 7 = 11 \text{ parts}

one part=4411=4 marbles\text{one part} = \frac{44}{11} = 4 \text{ marbles}

Red is 4 parts, so

4×4=164 \times 4 = 16

Check: blue is 7×4=28,7 \times 4 = 28\mathclose{,} and 16+28=44.16 + 28 = 44\mathclose{.} Correct.

Why each wrong option is wrong:

  • A, 44 — gave the value of one part and stopped.
  • B, 1111 — divided the 44 by the 4 in the ratio. The total is shared among all 11 parts, not among the red parts alone.
  • D, 2828 — worked correctly and gave the blue marbles.

Takeaway: add the parts first. 4 : 74 : 7 means 411\frac{4}{11} of the whole, not 47.\frac{4}{7}\mathclose{.} Then check your two answers add back to the total.


Q18Medium

Topic: A ratio in three parts

Three lengths of timber are cut from one plank in the ratio 5:3:2,5: 3: 2\mathclose{,} and the plank is 120 centimetres long altogether. How long is the longest piece, in centimetres?

F) 1212

G) 2424

H) 3636

J) 6060

Show the worked solution

Answer: J

Explanation

5+3+2=10 parts5 + 3 + 2 = 10 \text{ parts}

one part=12010=12 cm\text{one part} = \frac{120}{10} = 12 \text{ cm}

The longest piece is 5 parts:

5×12=60 cm5 \times 12 = 60 \text{ cm}

Check: 60+36+24=120.60 + 36 + 24 = 120\mathclose{.} Correct.

Why each wrong option is wrong:

  • F, 1212 — gave the size of one part.
  • G, 2424 — gave the shortest piece, 2 parts.
  • H, 3636 — gave the middle piece, 3 parts.

Takeaway: the method does not change with more parts — add them all, divide, then multiply by the part you were asked for. Read which one that is.


Q19Medium

Topic: Scaling a recipe by proportion

A biscuit recipe uses 3 cups of flour for every 8 biscuits it makes. A baker needs to make 20 biscuits for an order. How many cups of flour are needed?

A) 1.21.2

B) 7.57.5

C) 1515

D) 6060

Show the worked solution

Answer: B

Explanation

Set the two ratios equal, keeping flour on top in both:

3 cups8 biscuits=c20 biscuits\frac{3 \text{ cups}}{8 \text{ biscuits}} = \frac{c}{20 \text{ biscuits}}

Cross-multiply:

8c=60c=608=152=7.5 cups8c = 60 \qquad c = \frac{60}{8} = \frac{15}{2} = 7.5 \text{ cups}

Sanity check: 20 biscuits is two and a half times 8, so the flour should be two and a half times 3, which is 7.5. Correct.

Why each wrong option is wrong:

  • A, 1.21.2 — multiplied by 8 and divided by 20, the wrong way round.
  • C, 1515 — added: 12 more biscuits, so 12 more cups. A proportion scales by multiplying; adding the same amount to both breaks the ratio.
  • D, 6060 — multiplied 3×203 \times 20 and never divided by 8.

Takeaway: in a proportion, put the same quantity on top of both fractions. Then check the direction: more biscuits must mean more flour.


Q20Medium

Topic: Dividing two different quantities evenly

Leavonne bought 30 raffle tickets and 75 snack vouchers to share out equally among the members of a club, with no tickets and no vouchers left over. What is the largest number of members the club can have?

F) 55

G) 1515

H) 3030

J) 150150

Show the worked solution

Answer: G

Explanation

Every member gets a whole number of tickets and a whole number of vouchers, so the number of members must divide both 30 and 75. The largest such number is the greatest common factor.

30=2×3×575=3×5×530 = 2 \times 3 \times 5 \qquad 75 = 3 \times 5 \times 5

The factors they share are 3×5=15.3 \times 5 = 15\mathclose{.}

Check: 30÷15=230 \div 15 = 2 tickets each and 75÷15=575 \div 15 = 5 vouchers each, both whole. Correct.

Why each wrong option is wrong:

  • F, 55 — 5 divides both, but it is not the largest number that does.
  • H, 3030 — 30 does not divide 75.
  • J, 150150 — gave the lowest common multiple, 150. A multiple is bigger than both numbers; the number of members has to be smaller.

Takeaway: "shared out with none left over, as many groups as possible" is the greatest common factor. "Happens again at the same time" is the lowest common multiple. Decide which before you calculate.


Q21Medium

Topic: Reading a distance off a scale

A map is drawn to a scale of 1 centimetre to 25 kilometres, and two towns are 7.5 centimetres apart on it. How far apart, in kilometres, are the towns in reality?

A) 0.30.3

B) 2525

C) 32.532.5

D) 187.5187.5

Show the worked solution

Answer: D

Explanation

Each centimetre on the map stands for 25 real kilometres, so

7.5×25=187.5 km7.5 \times 25 = 187.5 \text{ km}

The direction matters: going from the map to the world, the number gets bigger, so you multiply.

Why each wrong option is wrong:

  • A, 0.30.3 — divided by the scale, which is the conversion the other way round, from the world to the map.
  • B, 2525 — repeated the scale factor.
  • C, 32.532.5 — added the two numbers.

Takeaway: decide which way the conversion goes before touching a calculator. Map to world, the number grows; world to map, it shrinks.


Q22Hard

Topic: A fraction of a total, worked backwards

At a bakery, one third of the pies sold on a particular day were apple, and a quarter of the remaining pies were cherry. Exactly 60 cherry pies were sold. How many pies were sold altogether?

F) 720720

G) 360360

H) 240240

J) 180180

Show the worked solution

Answer: G

Explanation

Let nn be the total. Apple pies take a third, so what remains is

n−13n=23nn - \frac{1}{3}n = \frac{2}{3}n

Cherry pies are a quarter of that:

14×23n=16n=60\frac{1}{4} \times \frac{2}{3}n = \frac{1}{6}n = 60

n=360n = 360

Check: 360 pies, 120 apple, 240 remaining, and a quarter of 240 is 60. Correct.

Why each wrong option is wrong:

  • F, 720720 — divided by both fractions separately instead of by their product.
  • H, 240240 — took the quarter from the whole day's sales, forgetting that the apple pies had already been removed.
  • J, 180180 — used the third rather than the quarter.

Takeaway: "of the remaining" means the fraction applies to what is left, not to the original. Write the leftover as a fraction of the total first.


Section 4 — Area, Perimeter and Volume in Context

These questions are not really geometry. They are arithmetic wearing a shape: work out an area or a volume, then multiply by a cost or divide into a supply.

The ACT gives you no formula sheet, so the formulas themselves have to be known. The ones this section needs:

shape formula
rectangle area =length×width= \text{length} \times \text{width}
rectangle perimeter =2(length+width)= 2(\text{length} + \text{width})
triangle area =12×base×height= \tfrac{1}{2} \times \text{base} \times \text{height}
circle area =πr2,= \pi r^2\mathclose{,} circumference =2πr= 2\pi r
box volume =length×width×height= \text{length} \times \text{width} \times \text{height}
cylinder volume =πr2h= \pi r^2 h

Chapter 8 has the complete list, with the reason each one is true. What matters here is the second half of the question: the units. An area in square metres multiplied by a cost per square metre gives dollars; anything else means something has gone wrong.


Q23Basic

Topic: Area, then a cost per unit area

A rectangular room measures 6 metres by 4 metres, and carpet for it costs $18 for each square metre laid. What is the total cost of carpeting the room?

A) 2424

B) 4242

C) 360360

D) 432432

Show the worked solution

Answer: D

Explanation

Area first:

6×4=24 square metres6 \times 4 = 24 \text{ square metres}

Then the cost:

24×18=43224 \times 18 = 432

Check the units: square metres ×\times dollars per square metre gives dollars. Correct.

Why each wrong option is wrong:

  • A, 2424 — gave the area, 24 square metres, and stopped. Stopping one step early is the commonest error in this chapter.
  • B, 4242 — added the cost rather than multiplying by it.
  • C, 360360 — used the perimeter, 2(6+4)=20.2(6 + 4) = 20\mathclose{.} Carpet covers a surface, so it is an area; perimeter would be for skirting board.

Takeaway: covering a floor is area; going round an edge is perimeter. Then finish the question — the area is rarely the answer.


Q24Medium

Topic: Volume in context, with a conversion

A rectangular trough measures 2 metres long, 1.5 metres wide and 0.4 metres deep, and it is to be filled to the brim with water. One cubic metre holds 1000 litres. How many litres of water does the trough hold?

F) 1.21.2

G) 1212

H) 12001200

J) 39003900

Show the worked solution

Answer: H

Explanation

Volume of a box is length ×\times width ×\times height:

2×1.5×0.4=1.2 cubic metres2 \times 1.5 \times 0.4 = 1.2 \text{ cubic metres}

Then convert:

1.2×1000=1200 litres1.2 \times 1000 = 1200 \text{ litres}

Why each wrong option is wrong:

  • F, 1.21.2 — gave the volume in cubic metres without converting to litres.
  • G, 1212 — the right shape of answer with a decimal point in the wrong place. Multiplying by 0.4 makes a number smaller, not ten times smaller.
  • J, 39003900 — added the three dimensions, 2+1.5+0.4=3.9,2 + 1.5 + 0.4 = 3.9\mathclose{,} before converting. Volume multiplies lengths; it never adds them.

Takeaway: volume multiplies three lengths. Then read the unit the answer is wanted in — it is often not the unit the measurements came in.


Q25Medium

Topic: Working back from an area to a missing side

A rectangular vegetable bed has an area of 45 square metres, and one of its sides measures 5 metres. The gardener wants to run a border all the way around the outside of the bed. What is the perimeter of the bed, in metres?

A) 99

B) 2828

C) 5050

D) 9090

Show the worked solution

Answer: B

Explanation

Find the missing side from the area:

5×w=45w=455=9 m5 \times w = 45 \qquad w = \frac{45}{5} = 9 \text{ m}

Now the perimeter, which is twice the sum of the two different sides:

2×(5+9)=28 m2 \times (5 + 9) = 28 \text{ m}

Why each wrong option is wrong:

  • A, 99 — found the missing side, 9, and stopped there.
  • C, 5050 — added an area to a length, which is not a meaningful operation — the units alone rule it out.
  • D, 9090 — doubled the area.

Takeaway: an area divided by one side gives the other side. Watch the units: you cannot add square metres to metres.


Q26Hard

Topic: Volume of a layer spread over an area

A rectangular driveway measuring 12 metres by 3 metres is to be covered with gravel to a uniform depth of 5 centimetres. Gravel is sold by the cubic metre. How many cubic metres of gravel are needed?

F) 1.81.8

G) 7.27.2

H) 3636

J) 180180

Show the worked solution

Answer: F

Explanation

Every measurement must be in the same unit before multiplying. The depth is 5 centimetres, and there are 100 centimetres in a metre:

5 cm=5100=0.05 m5 \text{ cm} = \frac{5}{100} = 0.05 \text{ m}

12×3×0.05=1.8 cubic metres12 \times 3 \times 0.05 = 1.8 \text{ cubic metres}

Why each wrong option is wrong:

  • G, 7.27.2 — divided by the depth instead of multiplying.
  • H, 3636 — gave the area of the driveway, forgetting the depth entirely.
  • J, 180180 — multiplied by 5 without converting, treating the depth as 5 metres. A driveway five metres deep is a swimming pool; a sanity check catches this.

Takeaway: convert every length to the same unit before you multiply, and then ask whether the answer is a sensible size for the thing described.


Section 5 — Averages and Medians

The mean is the total divided by how many there are. Rearranged, that gives the fact almost every ACT average question turns on:

total=mean×how many\text{total} = \text{mean} \times \text{how many}

Knowing the mean and the count gives you the total, and the total is what lets you recover a missing value or add a new one.

The median is the middle value once the data is in order. With an even number of values there is no single middle, so it is the mean of the middle two. Forgetting to sort first is the most common median error there is.


Q27Medium

Topic: Recovering a missing value from a mean

A teacher recorded five test results and found their mean was 20. Four of the five values were 12, 22, 15 and 25, and the fifth was mislaid. What was the fifth number?

A) 2020

B) 2626

C) 7474

D) 100100

Show the worked solution

Answer: B

Explanation

Five numbers with a mean of 20 must total

5×20=1005 \times 20 = 100

The four known values add to

12+22+15+25=7412 + 22 + 15 + 25 = 74

So the fifth is

100−74=26100 - 74 = 26

Check: 12+22+15+25+26=100,12 + 22 + 15 + 25 + 26 = 100\mathclose{,} and 100÷5=20.100 \div 5 = 20\mathclose{.} Correct.

Why each wrong option is wrong:

  • A, 2020 — assumed the missing value must equal the mean. It only does when the others happen to balance exactly, which is not the case here.
  • C, 7474 — gave the total of the four known values.
  • D, 100100 — gave the total of all five.

Takeaway: mean ×\times count == total. Get the total first, then everything else is subtraction.


Q28Medium

Topic: The median from a bar chart

A researcher recorded the number of birds visiting a feeder on each of six mornings. The bar chart shows the six counts.

Bar chart: Number of birds by Morning024681012MonTueWedThuFriSatMorningNumber of birds

What is the median of the six counts?

F) 66

G) 203\frac{20}{3}

H) 77

J) 99

Show the worked solution

Answer: H

Explanation

Read the six heights off the chart: 4, 9, 2, 11, 6 and 8.

Sort them first — this is the step people skip:

2,  4,  6,  8,  9,  112, \; 4, \; 6, \; 8, \; 9, \; 11

Six values, so there is no single middle one. The median is the mean of the third and fourth:

6+82=7\frac{6 + 8}{2} = 7

Why each wrong option is wrong:

  • F, 66 — picked a value from the middle of the unsorted list.
  • G, 203\frac{20}{3} — gave the mean, 40÷6,40 \div 6\mathclose{,} rather than the median.
  • J, 99 — gave the range, 11−2.11 - 2\mathclose{.}

Takeaway: sort, then find the middle. With an even count, average the middle two — and notice the median need not be one of the values in the list.


Q29Hard

Topic: A weighted average of two groups

One class of 20 students averaged 68 on a test, and a second class of 30 students averaged 78 on the same test. What is the mean score across both classes together?

A) 5050

B) 7272

C) 7373

D) 7474

Show the worked solution

Answer: D

Explanation

Go back to totals. The mean of a combined group is the combined total divided by the combined count:

class 1 total=20×68=1360\text{class 1 total} = 20 \times 68 = 1360 class 2 total=30×78=2340\text{class 2 total} = 30 \times 78 = 2340

overall mean=1360+234020+30=370050=74\text{overall mean} = \frac{1360 + 2340}{20 + 30} = \frac{3700}{50} = 74

Why each wrong option is wrong:

  • A, 5050 — gave the total number of students.
  • B, 7272 — gave the 30 students the 68 and the 20 students the 78: the class sizes the wrong way round.
  • C, 7373 — averaged the two averages, giving 73. That would only be right if the classes were the same size. The bigger class has the higher average, so the true answer must be pulled above 73 — which is a useful check.

Takeaway: averages cannot be averaged unless the groups are equal in size. Convert each to a total, add the totals, divide by the combined count.


Q30Medium

Topic: What an extreme value does to the mean and the median

A set of readings is 12,  14,  15,  13,  1612, \; 14, \; 15, \; 13, \; 16 — five values grouped closely together. A sixth reading of 6060 is then recorded, far outside the range of the others. Which statement about the effect of that new value is true?

F) The mean rises by much more than the median does

G) The median rises by much more than the mean does

H) Both rise by the same amount

J) Neither the mean nor the median changes

Show the worked solution

Answer: F

Explanation

Work out both, before and after.

Before, the five values total 70, so the mean is 70÷5=14.70 \div 5 = 14\mathclose{.} Sorted, they are 12,13,14,15,16,12, 13, 14, 15, 16\mathclose{,} so the median is also 14.

After adding 60, the six values total 130, so the mean is 130÷6=21.67.130 \div 6 = 21.67\mathclose{.} Sorted, they are 12,13,14,15,16,60,12, 13, 14, 15, 16, 60\mathclose{,} so the median is 14+152=14.5.\frac{14 + 15}{2} = 14.5\mathclose{.}

The mean moved by nearly 8; the median moved by a half.

The reason is structural: the mean uses the size of every value, so one huge number drags it a long way. The median only cares about position, so a huge number counts for no more than a slightly-bigger-than-average one.

Why each wrong option is wrong:

  • G, The median rises by much more than the mean does — has it exactly backwards.
  • H, Both rise by the same amount — they do not move together; that is the whole point of the question.
  • J, Neither the mean nor the median changes — both change, just by very different amounts.

Takeaway: an outlier drags the mean and barely moves the median. That is why house prices and salaries are reported as medians.


Section 6 — Expressing Numbers in Different Ways

The last part of this category is small but reliable: the same number written as a fraction, a decimal, a percentage, or in scientific notation, and questions about which of several values is largest.

38=0.375=37.5%4 500 000=4.5×106\frac{3}{8} = 0.375 = 37.5\% \qquad 4\,500\,000 = 4.5 \times 10^{6}

In scientific notation the first number is always at least 1 and less than 10. If you write 45×10545 \times 10^5 you have not finished.


Q31Basic

Topic: Writing a large number in scientific notation

Which of the following is 4 500 000 written in scientific notation?

A) 45×10545 \times 10^{5}

B) 4.5×1064.5 \times 10^{6}

C) 0.45×1070.45 \times 10^{7}

D) 4.5×1054.5 \times 10^{5}

Show the worked solution

Answer: B

Explanation

Move the decimal point until exactly one non-zero digit stands in front of it:

4 500 000⟶4.54\,500\,000 \longrightarrow 4.5

Count how many places it moved: 6. So the number is

4.5×1064.5 \times 10^{6}

Check by expanding: 4.5×1 000 000=4 500 000.4.5 \times 1\,000\,000 = 4\,500\,000\mathclose{.} Correct.

Why each wrong option is wrong:

  • A, 45×10545 \times 10^{5} — the right size, but not scientific notation: the leading number must be below 10.
  • C, 0.45×1070.45 \times 10^{7} — also the right size, but the leading number must be at least 1.
  • D, 4.5×1054.5 \times 10^{5} — counted one place too few, giving 450 000.

Takeaway: scientific notation needs exactly one non-zero digit before the decimal point. Two answers can be the same number and still only one of them is in the right form.


Q32Medium

Topic: Counting the integers between two values

How many integers are greater than 752\dfrac{75}{2} and less than 1313?\dfrac{131}{3}\mathclose{?}

F) 44

G) 55

H) 66

J) 77

Show the worked solution

Answer: H

Explanation

Convert both bounds:

752=37.51313=43.67\frac{75}{2} = 37.5 \qquad \frac{131}{3} = 43.67

The integers strictly between 37.5 and 43.67 are

38,  39,  40,  41,  42,  4338, \; 39, \; 40, \; 41, \; 42, \; 43

That is 6 of them.

The reliable way to count a run of consecutive integers is last−first+1:\text{last} - \text{first} + 1\mathclose{:}

43−38+1=643 - 38 + 1 = 6

The +1+1 is the fencepost: a fence from post 38 to post 43 has six posts, not five.

Why each wrong option is wrong:

  • F, 44 and G, 55 — fencepost errors, counting the gaps between the numbers rather than the numbers themselves.
  • J, 77 — included 37 or 44, which lie outside the range.

Takeaway: convert the bounds to decimals, write down the first and last integer that fit, then use last−first+1.\text{last} - \text{first} + 1\mathclose{.}


Q33Medium

Topic: Area of a wall, and how much paint it needs

A wall measures 8 metres long and 3 metres high, and one tin of paint covers 6 square metres. How many tins are needed to cover the wall once?

A) 44

B) 66

C) 2222

D) 2424

Show the worked solution

Answer: A

Explanation

Area first:

8×3=24 square metres8 \times 3 = 24 \text{ square metres}

Then divide by what one tin covers:

246=4 tins\frac{24}{6} = 4 \text{ tins}

Here it divides exactly. When it does not, you must round up — three and a bit tins means buying four, because half a tin is not sold.

Why each wrong option is wrong:

  • B, 66 — repeated the coverage figure.
  • C, 2222 — used the perimeter. Paint covers a surface, so it is an area.
  • D, 2424 — gave the area and stopped.

Takeaway: area ÷ coverage, then round up for anything sold whole.


Q34Hard

Topic: How much concrete a slab needs

A rectangular slab measures 4 metres by 2.5 metres and is poured to a uniform depth of 20 centimetres. Concrete is ordered by the cubic metre. How many cubic metres are needed?

F) 200200

G) 1010

H) 22

J) 0.20.2

Show the worked solution

Answer: H

Explanation

Convert the depth: 20 cm=0.2 m.20 \text{ cm} = 0.2 \text{ m}\mathclose{.}

4×2.5×0.2=2 cubic metres4 \times 2.5 \times 0.2 = 2 \text{ cubic metres}

Why each wrong option is wrong:

  • F, 200200 — used 20 metres as the depth. A slab twenty metres deep is a quarry; the sanity check catches this instantly.
  • G, 1010 — gave the area of the slab, forgetting the depth.
  • J, 0.20.2 — gave the depth on its own.

Takeaway: convert every length to the same unit before multiplying, then ask whether the answer is a sensible size.


Q35Basic

Topic: The same value written as a fraction, a decimal and a percent

What is 38\dfrac{3}{8} written as a percent?

A) 0.3750.375

B) 3.753.75

C) 37.537.5

D) 375375

Show the worked solution

Answer: C

Explanation

Divide, then multiply by 100:

38=0.3750.375×100=37.5%\frac{3}{8} = 0.375 \qquad 0.375 \times 100 = 37.5\%

Why each wrong option is wrong:

  • A, 0.3750.375 — stopped at the decimal. A percentage is that number times 100.
  • B, 3.753.75 — moved the decimal point one place instead of two.
  • D, 375375 — moved the decimal point three places. That would be more than the whole, and 38\frac{3}{8} is less than a half.

Takeaway: fraction → decimal → percent, in that order. A fraction below 1 must give a percentage below 100.


Q36Medium

Topic: Ordering values written in different forms

Which of the values 58,\dfrac{5}{8}\mathclose{,} 0.6,0.6\mathclose{,} 63%63\% and 35\dfrac{3}{5} is the greatest?

F) 58\dfrac{5}{8}

G) 0.60.6

H) 63%63\%

J) 35\dfrac{3}{5}

Show the worked solution

Answer: H

Explanation

Put everything into decimals:

58=0.6250.6=0.60063%=0.63035=0.600\frac{5}{8} = 0.625 \qquad 0.6 = 0.600 \qquad 63\% = 0.630 \qquad \frac{3}{5} = 0.600

The largest is 0.63.0.63\mathclose{.}

Note how close 0.6250.625 and 0.630.63 are — this is why converting all four is necessary rather than eyeballing them.

Why each wrong option is wrong:

  • F, 58\dfrac{5}{8} — 0.625,0.625\mathclose{,} second largest by five thousandths.
  • G, 0.60.6 and J, 35\dfrac{3}{5} — both are 0.6,0.6\mathclose{,} and they are equal to each other.

Takeaway: convert everything to decimals before comparing, and use the same number of decimal places so the comparison is a straight read.


Q37Medium

Topic: Rounding to a stated place value

What is 4.64724.6472 rounded to two decimal places?

A) 4.64.6

B) 4.644.64

C) 4.654.65

D) 4.74.7

Show the worked solution

Answer: C

Explanation

Two decimal places means keeping 4.644.64 and looking at the next digit, which is 7. Seven is 5 or more, so the last kept digit rounds up:

4.6472⟶4.654.6472 \longrightarrow 4.65

Only the digit immediately after matters. The 2 at the end plays no part.

Why each wrong option is wrong:

  • A, 4.64.6 — rounded to one decimal place.
  • B, 4.644.64 — cut the number off instead of rounding.
  • D, 4.74.7 — rounded the 4 up to 5 and then carried on rounding, which compounds one rounding into another.

Takeaway: look at one digit past the place you are keeping. Round once, not repeatedly.


Q38Medium

Topic: How much paint a room needs

A room's four walls have a combined area of 54 square metres, and one tin of paint covers 12 square metres. How many tins must be bought to give the walls one coat?

F) 44

G) 55

H) 1212

J) 648648

Show the worked solution

Answer: G

Explanation

5412=4.5 tins\frac{54}{12} = 4.5 \text{ tins}

Four tins would leave part of the wall bare, and half a tin cannot be bought, so round up to 5.

Why each wrong option is wrong:

  • F, 44 — rounded down. Four tins cover only 48 of the 54 square metres.
  • H, 1212 — repeated the coverage figure.
  • J, 648648 — multiplied where it should divide. The more a tin covers, the fewer tins are needed.

Takeaway: for anything sold whole — tins, buses, boxes — divide and then round up, whatever the decimal says.


Q39Basic

Topic: A decimal written as a fraction in lowest terms

Which of the following is 0.350.35 written as a fraction in lowest terms?

A) 135\frac{1}{35}

B) 720\frac{7}{20}

C) 35\frac{3}{5}

D) 72\frac{7}{2}

Show the worked solution

Answer: B

Explanation

Two decimal places means hundredths:

0.35=351000.35 = \frac{35}{100}

Both parts divide by 5:

35100=720\frac{35}{100} = \frac{7}{20}

Check: 7÷20=0.35.7 \div 20 = 0.35\mathclose{.} ✓

Why each wrong option is wrong:

  • A, 135\frac{1}{35} — inverted the fraction.
  • C, 35\frac{3}{5} — read only the 3, giving 0.6.
  • D, 72\frac{7}{2} — used tenths, giving 3.5, ten times too big.

Takeaway: count the decimal places to fix the power of ten — one place is tenths, two is hundredths — then cancel. Always divide back to check.


Q40Medium

Topic: Place value in a large number

What is the value of the digit 8 in the number 4825?4825\mathclose{?}

F) 88

G) 8080

H) 800800

J) 80008000

Show the worked solution

Answer: H

Explanation

Reading from the right: 5 is units, 2 is tens, 8 is hundreds, 4 is thousands.

8×100=8008 \times 100 = 800

Why each wrong option is wrong:

  • F, 88 — gave the digit rather than its value.
  • G, 8080 and J, 80008000 — counted the places wrongly by one in each direction.

Takeaway: a digit's value is the digit multiplied by its place. Count places from the right: units, tens, hundreds.


Q41Medium

Topic: The area of a floor, and the tiles it takes

A rectangular kitchen floor measures 3.5 metres by 4 metres, and each tile covers 0.25 square metres. Tiles are sold singly, and the floor must be fully covered. How many tiles are needed?

A) 3.53.5

B) 1414

C) 5656

D) 6060

Show the worked solution

Answer: C

Explanation

Area first:

3.5×4=14 square metres3.5 \times 4 = 14 \text{ square metres}

Each tile covers 0.25 m², so

140.25=56 tiles\frac{14}{0.25} = 56 \text{ tiles}

Dividing by a number below 1 makes the answer bigger, which is the check that catches most errors here — you need more tiles than square metres.

Why each wrong option is wrong:

  • A, 3.53.5 — multiplied the area by 0.25 instead of dividing by it.
  • B, 1414 — gave the area and stopped.
  • D, 6060 — used the distance round the floor, 15 metres, where the area is needed.

Takeaway: area ÷ coverage. Dividing by a fraction increases the count, so a smaller answer than the area means something has gone wrong.


Q42Medium

Topic: Comparing a fraction, a decimal and a percentage

Four values are to be ordered: 720,\dfrac{7}{20}\mathclose{,} 0.36,0.36\mathclose{,} 34%34\% and 13.\dfrac{1}{3}\mathclose{.} Which is the smallest?

F) 720\dfrac{7}{20}

G) 0.360.36

H) 34%34\%

J) 13\dfrac{1}{3}

Show the worked solution

Answer: J

Explanation

Convert everything to decimals:

720=0.3500.36=0.36034%=0.34013=0.333\frac{7}{20} = 0.350 \qquad 0.36 = 0.360 \qquad 34\% = 0.340 \qquad \frac{1}{3} = 0.333

The smallest is 13.\frac{1}{3}\mathclose{.}

Write them all to the same number of decimal places — the four values span only 0.027, so a rough comparison will not separate them.

Why each wrong option is wrong:

  • H, 34%34\% — 0.34,0.34\mathclose{,} and the closest rival, but still above 0.333.0.333\mathclose{.}
  • F, 720\dfrac{7}{20} — 0.35.0.35\mathclose{.}
  • G, 0.360.36 — the largest of the four.

Takeaway: convert to decimals, pad to equal length, then compare digit by digit. 13=0.333…\frac{1}{3} = 0.333\ldots is worth knowing on sight.


Q43Hard

Topic: How much paint a cylinder's curved surface needs

A cylindrical pillar has a radius of 0.5 metres and a height of 4 metres, and only its curved side is to be painted. What is that area, in square metres, in terms of π?\pi\mathclose{?}

A) π4\frac{\pi}{4}

B) π\pi

C) 2π2 \pi

D) 4π4 \pi

Show the worked solution

Answer: D

Explanation

Unroll the side: it is a rectangle as tall as the pillar and as wide as the circle around it.

width=2πr=2π(0.5)=πheight=4\text{width} = 2\pi r = 2\pi(0.5) = \pi \qquad \text{height} = 4

area=π×4=4π square metres\text{area} = \pi \times 4 = 4\pi \text{ square metres}

Why each wrong option is wrong:

  • A, π4\frac{\pi}{4} — the area of one circular end, πr2.\pi r^2\mathclose{.} The curved side is a rectangle rolled up: 2πr2\pi r round and hh high.
  • B, π\pi — used πr2h,\pi r^2 h\mathclose{,} which is a volume. Check the units: an area needs two lengths, not three.
  • C, 2π2 \pi — used πrh,\pi r h\mathclose{,} half the curved surface. The distance round the pillar is 2πr,2\pi r\mathclose{,} and the 2 matters.

Takeaway: a cylinder's curved surface is 2πrh2\pi r h — circumference times height. Picture unrolling it, and the formula stops needing to be remembered.


Q44Medium

Topic: Rounding to a significant figure

What is 0.0047360.004736 rounded to two significant figures?

F) 0.00470.0047

G) 0.004740.00474

H) 0.00480.0048

J) 0.0050.005

Show the worked solution

Answer: F

Explanation

The first significant figure is the 4 — leading zeros never count. So two significant figures means keeping 0.0047,0.0047\mathclose{,} and the next digit decides whether the 7 rounds up.

That next digit is 3, which is below 5, so the 7 stays:

0.004736⟶0.00470.004736 \longrightarrow 0.0047

Why each wrong option is wrong:

  • G, 0.004740.00474 — kept three significant figures instead of two.
  • H, 0.00480.0048 — rounded up, but the deciding digit is 3, not the 6 further along.
  • J, 0.0050.005 — gave one significant figure.

Takeaway: significant figures start at the first non-zero digit. Look at the one digit past where you stop, and ignore everything after it.


Q45Medium

Topic: Fencing a garden, and the cost of it

A rectangular garden measures 12 metres by 7 metres and is to be fenced all the way round, at $9 per metre of fencing. What is the total cost?

A) 3838

B) 171171

C) 342342

D) 756756

Show the worked solution

Answer: C

Explanation

The fence follows the perimeter:

2(12+7)=38 metres2(12 + 7) = 38 \text{ metres}

38×9=34238 \times 9 = 342

Why each wrong option is wrong:

  • A, 3838 — gave the perimeter and stopped.
  • B, 171171 — added the two sides once and forgot the garden has two of each.
  • D, 756756 — used the area. A fence goes round an edge; area would be for turfing it.

Takeaway: round an edge is perimeter; covering a surface is area. Decide which before choosing a formula.


Q46Medium

Topic: A percentage written as a decimal and a fraction

What is 6%6\% written as a decimal?

F) 0.00060.0006

G) 0.060.06

H) 0.60.6

J) 66

Show the worked solution

Answer: G

Explanation

6%=6100=0.066\% = \frac{6}{100} = 0.06

Moving the decimal point two places to the left is the same operation, and it is quicker: 6.0→0.06.6.0 \rightarrow 0.06\mathclose{.}

Why each wrong option is wrong:

  • F, 0.00060.0006 — divided by 100 twice.
  • H, 0.60.6 — moved the point one place, giving 60%.
  • J, 66 — left the number unchanged, so it now means 600%.

Takeaway: percent to decimal divides by 100 — two places left. Check by converting back.


Q47Medium

Topic: A fraction written as a repeating decimal

What is 511\dfrac{5}{11} written as a decimal, rounded to three decimal places?

A) 0.0450.045

B) 0.450.45

C) 0.4540.454

D) 0.4550.455

Show the worked solution

Answer: D

Explanation

511=0.454545…\frac{5}{11} = 0.454545\ldots

The digits 45 repeat. To three decimal places, look at the fourth digit, which is 5 — that is 5 or more, so the third place rounds up:

0.4545…⟶0.4550.4545\ldots \longrightarrow 0.455

Why each wrong option is wrong:

  • A, 0.0450.045 — a decimal-place slip; 511\frac{5}{11} is close to a half, not to a twentieth.
  • B, 0.450.45 — rounded to two decimal places where three were asked for.
  • C, 0.4540.454 — cut the number off at three places instead of rounding.

Takeaway: a repeating decimal still rounds by the ordinary rule — look at the next digit. And sanity-check the size: 511\frac{5}{11} is a little under 12.\frac{1}{2}\mathclose{.}