Mathbench

Chapter 5 — Geometry

Geometry is 17 to 20% of the test — eight questions — and on the ACT it is larger and more varied than on the SAT. Circles, solids, polygons and coordinate geometry all appear, and there is no formula sheet to lean on.

That last point governs this whole chapter. Every formula used here is in Chapter 8, with the reason it is true. Learn them there; use them here.

One habit worth building from the start: draw the picture. Almost every ACT geometry question describes a shape in words, and a sketch with the numbers written on it turns a confusing paragraph into an obvious calculation. It takes fifteen seconds and it is the single most reliable way to gain marks in this category.

Topics covered: angles in triangles and on lines · isosceles and equilateral triangles · polygons and quadrilaterals · similar figures · circles, arcs and sectors · the equation of a circle · solids and volume · coordinate geometry


Section 1 — Angles, Triangles and Polygons

The facts this section needs, all of them worth knowing by heart:

That last formula covers quadrilaterals (360°360°), pentagons (540°540°), hexagons (720°720°) and everything beyond, so it is one fact rather than five.


Q1Basic

Topic: The third angle of a triangle

A surveyor measures two of the three interior angles of a triangular plot of land and records them as 47°47° and 68°68°. What is the measure of the third angle?

A) 115115

B) 4545

C) 6565

D) 113113

Show the worked solution

Answer: C

Explanation

The three angles of a triangle add to 180°180°:

47+68+x=18047 + 68 + x = 180 115+x=180115 + x = 180 x=65°x = 65°

Check: 47+68+65=18047 + 68 + 65 = 180. Correct.

Why each wrong option is wrong:

  • A, 115115 — added the two given angles and stopped. 115 is a step on the way, not the answer.
  • B, 4545 and D, 113113 — arithmetic slips. Always add all three of your angles at the end; it takes two seconds and catches every one of these.

Takeaway: the angles of a triangle add to 180°180°. Subtract the sum of the two you know, then add all three back to check.


Q2Medium

Topic: The base angles of an isosceles triangle

A roof truss is built as triangle ABCABC with AB=ACAB = AC, making it isosceles, and the angle at the apex AA measures 40°40°. What is the measure of angle BB?

F) 4040

G) 140140

H) 100100

J) 7070

Show the worked solution

Answer: J

Explanation

AB=ACAB = AC, so the angles opposite those sides — angles CC and BB — are equal. Call each of them xx.

40+x+x=18040 + x + x = 180 2x=1402x = 140 x=70°x = 70°

Check: 40+70+70=18040 + 70 + 70 = 180. Correct.

Which angles are equal? The ones opposite the equal sides. ABAB and ACAC both start at AA, so the equal angles are the other two, BB and CC. Getting this backwards is the usual error, and drawing the triangle makes it obvious.

Why each wrong option is wrong:

  • F, 4040 — assumed the triangle is equilateral.
  • G, 140140 — found the 140°140° left over and forgot it is shared between two angles.
  • H, 100100 — treated angle CC as 40°40° as well.

Takeaway: equal sides face equal angles. Subtract the odd angle from 180°180°, then halve what is left.


Q3Medium

Topic: An exterior angle of a triangle

In a triangle, the two interior angles not adjacent to a particular exterior angle measure 52°52° and 61°61°. What is the measure of that exterior angle?

A) 6767

B) 113113

C) 128128

D) 119119

Show the worked solution

Answer: B

Explanation

The exterior angle rule:

exterior angle=52+61=113°\text{exterior angle} = 52 + 61 = 113°

Why it works: the third interior angle is 1805261=67°180 - 52 - 61 = 67°, and the exterior angle sits on a straight line with it, so it is 18067=113°180 - 67 = 113°. The rule is just those two steps combined — which is why it saves time.

Why each wrong option is wrong:

  • A, 6767 — gave the third interior angle, the one the exterior angle sits next to.
  • C, 128128 and D, 119119 — used only one of the two given angles.

Takeaway: an exterior angle equals the sum of the two remote interior angles. If you forget the rule, find the third angle and subtract from 180°180° — same answer, one more step.


Q4Medium

Topic: The interior angles of a polygon

A regular hexagon is used as a tile pattern, and each of its six interior angles is the same size. What is the measure of each interior angle?

F) 120120

G) 6060

H) 720720

J) 9090

Show the worked solution

Answer: F

Explanation

Total interior angles:

(62)×180=4×180=720°(6 - 2) \times 180 = 4 \times 180 = 720°

The hexagon is regular, so all six angles are equal:

7206=120°\frac{720}{6} = 120°

Why each wrong option is wrong:

  • G, 6060 — gave the exterior angle. The exterior angles of any polygon add to 360°360°, so each is 3606=60°\frac{360}{6} = 60° — and indeed 120+60=180120 + 60 = 180, as they sit on a straight line together.
  • H, 720720 — gave the total for all six angles.
  • J, 9090 — divided by 8 rather than 6.

Takeaway: (n2)×180(n-2) \times 180 is the total. Divide by nn for one angle of a regular polygon. The exterior angles always total 360°360°, whatever nn is.


Q5Hard

Topic: Similar triangles in a shadow problem

A flagpole casts a shadow 9 metres long at the same moment that a 2-metre post casts a shadow 1.5 metres long on level ground. How tall is the flagpole, in metres?

A) 66

B) 1212

C) 274\frac{27}{4}

D) 135135

Show the worked solution

Answer: B

Explanation

Draw both triangles. Each has a vertical object and a horizontal shadow, and the sun makes the same angle in both — so they are similar, and matching sides are in the same ratio.

Set up the proportion with height on top in both:

flagpole heightflagpole shadow=post heightpost shadow\frac{\text{flagpole height}}{\text{flagpole shadow}} = \frac{\text{post height}}{\text{post shadow}}

h9=21.5\frac{h}{9} = \frac{2}{1.5}

h=9×21.5=9×43=12 mh = 9 \times \frac{2}{1.5} = 9 \times \frac{4}{3} = 12 \text{ m}

Sanity check: the post is taller than its shadow (22 against 1.51.5), so the flagpole must be taller than its 9-metre shadow. 12 is. Correct.

Why each wrong option is wrong:

  • A, 66 — paired the wrong sides together.
  • C, 274\frac{27}{4} — set the proportion up upside down, which makes the flagpole shorter than its shadow and fails the sanity check.
  • D, 135135 — multiplied the numbers without forming a ratio.

Takeaway: similar shapes give equal ratios. Put the same measurement on top of both fractions, then check the answer is on the right side of the number you started with.


Section 2 — Circles

Four facts carry almost every ACT circle question:

circumference=2πrarea=πr2\text{circumference} = 2\pi r \qquad \text{area} = \pi r^{2}

An arc is part of the circumference and a sector is a slice of the area. Both are the same fraction of the whole, and that fraction is central angle360\dfrac{\text{central angle}}{360}:

arc length=θ360×2πrsector area=θ360×πr2\text{arc length} = \frac{\theta}{360} \times 2\pi r \qquad \text{sector area} = \frac{\theta}{360} \times \pi r^{2}

And the equation of a circle with centre (h,k)(h, k) and radius rr:

(xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2

Note the minus signs in the brackets and that the right-hand side is r2r^2, not rr. Both are where the marks go.


Q6Medium

Topic: The area of a sector

A circular flower bed of radius 6 metres is to be divided into wedge-shaped planting sections. One section is a sector with a central angle of 60°60° measured at the centre of the bed. What is the area of that sector?

F) 6π6 \pi

G) 36π36 \pi

H) 2π2 \pi

J) 12π12 \pi

Show the worked solution

Answer: F

Explanation

A 60°60° sector is 60360=16\frac{60}{360} = \frac{1}{6} of the circle.

The whole circle's area:

πr2=π×36=36π\pi r^2 = \pi \times 36 = 36\pi

One sixth of it:

16×36π=6π square metres\frac{1}{6} \times 36\pi = 6\pi \text{ square metres}

Why each wrong option is wrong:

  • G, 36π36 \pi — gave the area of the whole circle without taking the fraction.
  • H, 2π2 \pi — used the arc-length formula, which gives a length, not an area. Check the units: an area needs r2r^2 in it.
  • J, 12π12 \pi — doubled the correct sector.

Takeaway: a sector is θ360\frac{\theta}{360} of the circle. Use πr2\pi r^2 for area and 2πr2\pi r for arc length, and let the units tell you which you need.


Q7Medium

Topic: Reading the centre and radius from a circle's equation

A radio transmitter's coverage area is described in the xyxy-plane by (x4)2+(y+3)2=25(x - 4)^2 + (y + 3)^2 = 25. What are its centre and radius?

A) (4, 3, 25)\left( -4, \ 3, \ 25\right)

B) (4, 3, 5)\left( -4, \ 3, \ 5\right)

C) (4, 3, 25)\left( 4, \ -3, \ 25\right)

D) (4, 3, 5)\left( 4, \ -3, \ 5\right)

Show the worked solution

Answer: D

Explanation

The standard form is

(xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2

with centre (h,k)(h, k) and radius rr.

Match it up carefully. (x4)2(x - 4)^2 gives h=4h = 4. For the yy term, rewrite (y+3)2(y + 3)^2 as (y(3))2(y - (-3))^2, so k=3k = -3.

The right-hand side is r2=25r^2 = 25, so r=5r = 5take the square root.

Centre (4,3)(4, -3), radius 5.

Why each wrong option is wrong:

  • B, (4, 3, 5)\left( -4, \ 3, \ 5\right) — copied the signs as they appear in the brackets. The formula has a minus built in, so a +3+3 inside means 3-3 in the centre.
  • C, (4, 3, 25)\left( 4, \ -3, \ 25\right) — gave 25 as the radius. The equation gives r2r^2.
  • A, (4, 3, 25)\left( -4, \ 3, \ 25\right) — both errors together.

Takeaway: the signs in the brackets flip, and the number on the right is r2r^2. Rewrite (y+3)(y+3) as (y(3))(y-(-3)) if the sign flip is not automatic yet.


Q8Hard

Topic: Finding the radius from a diameter's endpoints

A circular arena is drawn on a plan with a diameter running between the endpoints (1,2)(1, 2) and (7,10)(7, 10). What is the radius?

F) 1010

G) 55

H) 1414

J) 10\sqrt{10}

Show the worked solution

Answer: G

Explanation

Find the distance between the two points first:

d=(71)2+(102)2=62+82=36+64=100=10d = \sqrt{(7-1)^2 + (10-2)^2} = \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10

That distance is the diameter, so the radius is half of it:

r=102=5r = \frac{10}{2} = 5

The 6, 8, 10 triangle here is a scaled 3, 4, 5 — worth recognising, because it saves the arithmetic entirely.

Why each wrong option is wrong:

  • F, 1010 — gave the diameter. Stopping one step early is the usual error in this question, which is exactly why it says "radius".
  • H, 1414 — added the horizontal and vertical differences without squaring. That is the distance you would walk along two sides, not the straight line.
  • J, 10\sqrt{10} — did not square the differences before adding.

Takeaway: the distance formula is Pythagoras in disguise. And read the last word — diameter or radius decides whether you halve.


Section 3 — Solids and Volume

The volumes worth knowing, all of which are in Chapter 8 with their reasons:

solid volume
box (rectangular prism) lwhlwh
cylinder πr2h\pi r^2 h
any prism (area of cross-section) ×\times length
sphere 43πr3\tfrac{4}{3}\pi r^3
cone 13πr2h\tfrac{1}{3}\pi r^2 h

The ACT also likes scaling: what happens to area and volume when a length changes. The rule is worth more than any single formula:

If every length is multiplied by kk, then every area is multiplied by k2k^2 and every volume by k3k^3.


Q9Medium

Topic: The volume of a cylinder

A cylindrical water tank has a base of radius 3 metres and stands 10 metres tall. What is its volume?

A) 60π60 \pi

B) 30π30 \pi

C) 90π90 \pi

D) 900π900 \pi

Show the worked solution

Answer: C

Explanation

V=πr2h=π×32×10=π×9×10=90πV = \pi r^2 h = \pi \times 3^2 \times 10 = \pi \times 9 \times 10 = 90\pi

Square the radius first, then multiply by the height. Doing it in the other order is fine too, as long as only the radius gets squared.

Why each wrong option is wrong:

  • A, 60π60 \pi — used 2πrh2\pi r h, which is the curved surface area, not a volume. A volume needs three lengths multiplied together, and this has only two.
  • B, 30π30 \pi — forgot to square the radius.
  • D, 900π900 \pi — squared 3×103 \times 10 rather than just the 3.

Takeaway: πr2h\pi r^2 h — only the radius is squared. If your expression has fewer than three lengths multiplied together, it is not a volume.


Q10Hard

Topic: Scaling a solid

A spherical balloon is inflated until its radius is three times what it was before. By what factor does its volume increase?

F) 33

G) 99

H) 1212

J) 2727

Show the worked solution

Answer: J

Explanation

The volume of a sphere is 43πr3\frac{4}{3}\pi r^3. Replacing rr with 3r3r:

43π(3r)3=43π27r3\frac{4}{3}\pi (3r)^3 = \frac{4}{3}\pi \cdot 27 r^3

so the volume is 27 times what it was. The bracket matters: (3r)3(3r)^3 cubes the 3 as well as the rr.

The general rule: multiply every length by kk and volume multiplies by k3k^3. Here k=3k = 3, so 33=273^3 = 27.

Why each wrong option is wrong:

  • F, 33 — assumed volume grows in proportion to length.
  • G, 99 — used k2k^2, which is the factor for area, not volume.
  • H, 1212 — brought the 43\frac{4}{3} into the scaling. Constants in the formula do not affect how it scales; only the power of rr does.

Takeaway: lengths scale by kk, areas by k2k^2, volumes by k3k^3. Cube the bracket, not just the letter inside it.


Q11Medium

Topic: The surface area of a box

A closed cardboard box measures 4 by 3 by 2 units, and every face has to be covered. What is its surface area?

A) 5252

B) 2424

C) 2626

D) 1818

Show the worked solution

Answer: A

Explanation

The six faces come in three pairs, one pair for each combination of two dimensions:

4×3=12(twice)4×2=8(twice)3×2=6(twice)4 \times 3 = 12 \quad (\text{twice}) \qquad 4 \times 2 = 8 \quad (\text{twice}) \qquad 3 \times 2 = 6 \quad (\text{twice})

surface area=2(12+8+6)=2×26=52\text{surface area} = 2(12 + 8 + 6) = 2 \times 26 = 52

Why each wrong option is wrong:

  • B, 2424 — gave the volume, 4×3×24 \times 3 \times 2. Check the units: a surface area is in square units, and multiplying three lengths gives cubic units.
  • C, 2626 — added one of each face and forgot the box has two of each.
  • D, 1818 — added the dimensions rather than multiplying them in pairs.

Takeaway: a box has six faces in three matching pairs, so 2(lw+lh+wh)2(lw + lh + wh). If you find yourself multiplying all three dimensions together, you are calculating a volume.


Section 4 — Coordinate Geometry

Three formulas connect algebra to the picture, and all three come from Pythagoras or from counting:

distance=(x2x1)2+(y2y1)2\text{distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

midpoint=(x1+x22,  y1+y22)\text{midpoint} = \left(\frac{x_1 + x_2}{2}, \; \frac{y_1 + y_2}{2}\right)

slope=y2y1x2x1\text{slope} = \frac{y_2 - y_1}{x_2 - x_1}

The midpoint is an average, so it adds; distance and slope both subtract. Mixing up which one adds is the commonest error here.


Q12Basic

Topic: The midpoint of a line segment

In the standard (x,y)(x, y) coordinate plane, a line segment has endpoints (3,8)(3, 8) and (1,4)(-1, -4). What is the midpoint?

F) (2, 6)\left( 2, \ 6\right)

G) (4, 12)\left( 4, \ 12\right)

H) (1, 2)\left( 1, \ 2\right)

J) (2, 6)\left( -2, \ -6\right)

Show the worked solution

Answer: H

Explanation

Average each coordinate separately:

x:  3+(1)2=22=1x: \; \frac{3 + (-1)}{2} = \frac{2}{2} = 1

y:  8+(4)2=42=2y: \; \frac{8 + (-4)}{2} = \frac{4}{2} = 2

Midpoint (1,2)(1, 2).

A good check: the midpoint must lie between the two endpoints in both coordinates. 11 is between 1-1 and 33; 22 is between 4-4 and 88. Correct.

Why each wrong option is wrong:

  • F, (2, 6)\left( 2, \ 6\right) and J, (2, 6)\left( -2, \ -6\right) — subtracted instead of adding. Both fail the "between" check.
  • G, (4, 12)\left( 4, \ 12\right) — gave the differences without halving.

Takeaway: the midpoint adds and halves; distance and slope subtract. Then check your answer lies between the two endpoints.


Q13Hard

Topic: Counting points at a fixed distance

In the xyxy-plane, a point must lie exactly 5 units from the origin and also exactly 3 units from the horizontal axis. How many such points are there?

A) 11

B) 22

C) 33

D) 44

Show the worked solution

Answer: D

Explanation

"5 units from the origin" means

x2+y2=25x^2 + y^2 = 25

"3 units from the horizontal axis" means the distance from the xx-axis is 3, so

y=3ory=3y = 3 \quad \text{or} \quad y = -3

Take y=3y = 3:

x2+9=25x2=16x=±4x^2 + 9 = 25 \quad\Longrightarrow\quad x^2 = 16 \quad\Longrightarrow\quad x = \pm 4

That gives (4,3)(4, 3) and (4,3)(-4, 3). Now y=3y = -3 gives the same two xx values, so (4,3)(4, -3) and (4,3)(-4, -3).

Four points in total.

Why each wrong option is wrong:

  • A, 11, B, 22 and C, 33 — each misses some of the sign combinations. There are two independent choices, ±\pm for xx and ±\pm for yy, so 2×2=42 \times 2 = 4.

Takeaway: "a distance from an axis" allows both sides of it, and a squared equation gives both signs. Sketch the circle and the two lines — the four crossings are then impossible to miscount.


Q14Medium

Topic: The distance between two points

A survey records two markers at (2,1)(-2, 1) and (4,9)(4, 9) in the xyxy-plane, and the straight-line distance between them is needed. What is the distance?

F) 1414

G) 1010

H) 14\sqrt{14}

J) 100100

Show the worked solution

Answer: G

Explanation

Find the two gaps first:

across: 4(2)=6up: 91=8\text{across: } 4 - (-2) = 6 \qquad \text{up: } 9 - 1 = 8

Then Pythagoras:

62+82=36+64=100=10\sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10

Another 6, 8, 10 triangle. The 3-4-5 family turns up constantly on the ACT.

Why each wrong option is wrong:

  • F, 1414 — added the gaps, which is the distance walked along two sides of the right triangle rather than across it. It is always larger than the true distance.
  • H, 14\sqrt{14} — added before squaring.
  • J, 100100 — did everything right and forgot the square root.

Takeaway: find both gaps, square, add, then root. Watch the double negative in 4(2)4 - (-2); that is where the arithmetic usually goes wrong.


Q15Medium

Topic: Corresponding sides of similar triangles

Two triangles are similar, and the sides of the smaller measure 4, 6 and 8 units. The longest side of the larger triangle measures 20 units. What is the perimeter of the larger triangle?

A) 4545

B) 1818

C) 3030

D) 5454

Show the worked solution

Answer: A

Explanation

The scale factor comes from the pair of corresponding sides you know — the longest of each:

k=208=2.5k = \frac{20}{8} = 2.5

Perimeter scales by the same factor as any length:

(4+6+8)×2.5=18×2.5=45(4 + 6 + 8) \times 2.5 = 18 \times 2.5 = 45

Why each wrong option is wrong:

  • B, 1818 — gave the smaller triangle's perimeter.
  • C, 3030 — replaced the longest side and left the other two unscaled.
  • D, 5454 — used a scale factor of 3.

Takeaway: find the scale factor from a matching pair, then apply it to every length. Perimeter scales by kk; area would scale by k2k^2.


Q16Medium

Topic: A missing side in similar triangles

Two triangles are similar. The smaller has sides of 3 and 5 units; the larger has a side of 12 corresponding to the 3. What is the length of the larger triangle's side corresponding to the 5?

F) 1414

G) 1515

H) 2020

J) 54\frac{5}{4}

Show the worked solution

Answer: H

Explanation

Find the scale factor from the pair you know:

k=123=4k = \frac{12}{3} = 4

Apply it to the other side:

5×4=205 \times 4 = 20

Why each wrong option is wrong:

  • F, 1414 — added the difference (9) rather than multiplying by the ratio. Similar figures scale by multiplication, not addition — adding a fixed amount would change the shape.
  • G, 1515 — used 3 as the scale factor.
  • J, 54\frac{5}{4} — divided instead of multiplying, shrinking the larger triangle.

Takeaway: similar figures scale by a ratio, never by a difference. Find the factor from a known pair, then apply it.


Q17Hard

Topic: Areas of similar figures

Two similar rectangles have corresponding sides in the ratio 2:52: 5. What is the ratio of their areas?

A) 25\frac{2}{5}

B) 45\frac{4}{5}

C) 425\frac{4}{25}

D) 8125\frac{8}{125}

Show the worked solution

Answer: C

Explanation

Lengths are in the ratio 2:52 : 5, so both dimensions scale by 52\frac{5}{2} going from the smaller to the larger. Area is length × width, so the factor applies twice:

area ratio=22:52=4:25\text{area ratio} = 2^2 : 5^2 = 4 : 25

Why each wrong option is wrong:

  • A, 25\frac{2}{5} — used the length ratio unchanged.
  • B, 45\frac{4}{5} — squared only the 2.
  • D, 8125\frac{8}{125} — cubed, which is the factor for volumes.

Takeaway: lengths scale by kk, areas by k2k^2, volumes by k3k^3. Square both parts of the ratio.


Q18Medium

Topic: Congruent triangles

Two triangles have three pairs of equal sides. Which of the following must be true of them?

F) Their corresponding angles are equal and their areas are equal

G) Their corresponding angles are equal but their areas may differ

H) Their areas are equal but their angles may differ

J) Neither the angles nor the areas need match

Show the worked solution

Answer: F

Explanation

Three pairs of equal sides is the SSS condition, and it makes the triangles congruent — identical in every respect, not merely the same shape.

So the corresponding angles are equal and the areas are equal. A triangle's three sides fix it completely: there is no way to build two different triangles from the same three lengths.

Why each wrong option is wrong:

  • G, Their corresponding angles are equal but their areas may differ — describes similar triangles, which share angles but may differ in size. Congruent is stronger.
  • H, Their areas are equal but their angles may differ — equal areas do not on their own force equal angles, but here the angles are equal too.
  • J, Neither the angles nor the areas need match — both do match.

Takeaway: similar means same shape, possibly different size. Congruent means identical. Three equal sides give congruence, and congruence gives you everything.


Q19Medium

Topic: An angle in a regular polygon

A regular octagon is used as a paving stone, and each of its eight interior angles is the same size. What is each interior angle?

A) 135135

B) 4545

C) 10801080

D) 120120

Show the worked solution

Answer: A

Explanation

Total interior angles:

(82)×180=6×180=1080°(8 - 2) \times 180 = 6 \times 180 = 1080°

Shared equally between eight angles:

10808=135°\frac{1080}{8} = 135°

Why each wrong option is wrong:

  • B, 4545 — gave the exterior angle, 3608=45°\frac{360}{8} = 45°. Note 135+45=180135 + 45 = 180, as they sit on a straight line together.
  • C, 10801080 — gave the total rather than one angle.
  • D, 120120 — used a hexagon's answer.

Takeaway: (n2)×180(n-2) \times 180 is the total; divide by nn for one angle. Exterior angles always total 360°360°, so each is 360n\frac{360}{n}.


Q20Medium

Topic: The area of a parallelogram

A parallelogram-shaped panel has a base of 15 centimetres and a perpendicular height of 8 centimetres. What is the area of the panel, in square centimetres?

F) 150150

G) 6060

H) 120120

J) 4646

Show the worked solution

Answer: H

Explanation

The area of a parallelogram is base times perpendicular height:

15×8=120 square centimetres15 \times 8 = 120 \text{ square centimetres}

The 10 cm slanted side is there to be ignored. Height always means the perpendicular distance between the two parallel sides, never the sloping edge — and on the ACT that extra length is offered precisely because it is tempting.

Why each wrong option is wrong:

  • F, 150150 — used the slanted side, which overstates the area. The perpendicular height is always the shorter of the two.
  • G, 6060 — halved it, which is the triangle formula. A parallelogram is two triangles, so it does not carry the half.
  • J, 4646 — added the two lengths, giving something in the wrong units entirely.

Takeaway: a parallelogram is base × perpendicular height, with no half. A slanted side given alongside the height is there to be left alone.