Mathbench

Chapter 2 — Lines, Linear Functions and Systems

This is the other half of the SAT's algebra, and between them Chapters 1 and 2 account for roughly 35% of the Math section.

Everything here rests on one picture. A linear relationship is one that changes by the same amount every step: add 1 to xx and yy always moves by the same fixed number. That fixed number is the slope, and almost every question in this chapter is really asking about it — sometimes by name, more often disguised as "rate of change", "per hour", "for each additional", or a pair of points on a graph.

A note on the calculator. The built-in graphing calculator is genuinely useful here, more than anywhere else on the test. If a question gives you two equations and asks where they meet, you can type both in and read the intersection off the screen. Learn to do it algebraically as well, because a question can hand you letters instead of numbers — but know that the graph is there.

Topics covered: slope from two points · the three forms of a line · parallel and perpendicular lines · interpreting a linear model · solving systems by substitution and elimination · systems with no solution or infinitely many


Section 1 — Slope

The slope of a line is how much yy changes for each 1 that xx increases:

m=y2y1x2x1=riserun=change in ychange in xm = \frac{y_2 - y_1}{x_2 - x_1} = \frac{\text{rise}}{\text{run}} = \frac{\text{change in } y}{\text{change in } x}

This formula is not on the reference sheet. Learn it.

Two things to hold on to:

Two special cases the test likes:

Line Slope
Horizontal (y=4y = 4) 00
Vertical (x=4x = 4) undefined

Q1Basic

Topic: Slope from two points

A seedling's height was measured on two occasions during an experiment, and the two measurements were recorded in the table below.

Day, xx 2 6
Height in centimetres, yy 3 11

A) 12\frac{1}{2}

B) 22

C) 2-2

D) 74\frac{7}{4}

Show the worked solution

Answer: B

Explanation

Label the points and subtract in a consistent order. Take (2,3)(2, 3) as the first and (6,11)(6, 11) as the second:

m=11362=84=2m = \frac{11 - 3}{6 - 2} = \frac{8}{4} = 2

Check it makes sense: as xx goes from 2 to 6 the point rises from 3 to 11, so the line goes up — and the slope is positive. ✓

It does not matter which point you call first, as long as you are consistent. Starting from (6,11)(6, 11) instead:

m=31126=84=2m = \frac{3 - 11}{2 - 6} = \frac{-8}{-4} = 2

Same answer. The two minus signs cancel, which is exactly why consistency is the only rule.

Why each wrong option is wrong:

  • A, 12\frac{1}{2} — the change in xx over the change in yy, upside down. Slope is rise over run: yy on top.
  • B is the answer.
  • C, 2-2 — subtracted the yy values in one order and the xx values in the other. That is the inconsistency warned about above, and it always produces the right number with the wrong sign.
  • D, 74\frac{7}{4} — added the coordinates instead of subtracting them. Slope is about change, so it is always a subtraction.

Takeaway: m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}, with yy on top and the same order on both. Then check the sign against whether the line should be rising or falling.


Q2Medium

Topic: Slope as a rate of change

A tree's height was 140 cm after 2 years and 260 cm after 8 years. If the growth is linear, by how many centimetres does the tree grow each year?

A) 6060

B) 1212

C) 652\frac{65}{2}

D) 2020

Show the worked solution

Answer: D

Explanation

"How much per year" is a slope. The two points are (2,140)(2, 140) and (8,260)(8, 260), where xx is years and yy is height:

m=26014082=1206=20m = \frac{260 - 140}{8 - 2} = \frac{120}{6} = 20

The tree grows 20 cm a year.

Check it: from year 2, six years pass to reach year 8, and 6×20=1206 \times 20 = 120 cm of growth — which takes 140 cm up to 260 cm ✓

Why each wrong option is wrong:

  • B, 1212 — added the two years instead of subtracting them. The gap is 6 years, not 10.
  • C, 652\frac{65}{2} — divided a height by a year, which is what you would do if the tree had been 0 cm tall at year 0. It was not; it was 140 cm at year 2.
  • A, 6060 — divided the growth by 2 rather than by the 6-year gap.

Takeaway: "Per year", "per hour", "for each" all mean slope. Use the gap between the two xx values, never one of the values on its own.


Q3Medium

Topic: Slope of a horizontal line

A sensor recorded the same reading at two different positions along a bench, and those readings are plotted as the points (3,5)(-3, 5) and (4,5)(4, 5). What is its slope?

A) 11

B) 77

C) 57\frac{5}{7}

D) 00

Show the worked solution

Answer: D

Explanation

Both points have the same yy-coordinate, 5. So there is no rise at all:

m=554(3)=07=0m = \frac{5 - 5}{4 - (-3)} = \frac{0}{7} = 0

The line is horizontal — it is the line y=5y = 5. Walk along it and you never go up or down, so the slope is zero.

Be careful with the pair this question sits next to. Zero on top gives slope 0; zero on the bottom gives an undefined slope, and that is a vertical line like x=5x = 5. They sound similar and they are opposites.

yy values equal → 0something\frac{0}{\text{something}} horizontal, slope 00
xx values equal → something0\frac{\text{something}}{0} vertical, slope undefined

Why each wrong option is wrong:

  • A, 11 — there is no default slope; it has to be computed.
  • B, 77 — the horizontal distance between the points, which is the denominator, not the slope.
  • C, 57\frac{5}{7} — used the yy-coordinate 5 as though it were the rise. The rise is the change in yy, which here is zero.

Takeaway: Same yy means horizontal and slope 0. Same xx means vertical and slope undefined. Check whether the coordinates repeat before reaching for the formula.


Section 2 — The Forms of a Line

The same line can be written three ways. The test moves between them constantly, and each form is convenient for a different question.

Form Looks like Read off it immediately
Slope-intercept y=mx+by = mx + b slope mm, yy-intercept bb
Point-slope yy1=m(xx1)y - y_1 = m(x - x_1) slope mm, a point (x1,y1)(x_1, y_1)
Standard Ax+By=CAx + By = C both intercepts, quickly

Slope-intercept is the one to convert into. If a question gives you 3x+4y=123x + 4y = 12 and asks for the slope, rearrange to y=34x+3y = -\frac34 x + 3 and read it off. Guessing the slope from the standard form's coefficients is where marks disappear — the slope of Ax+By=CAx + By = C is AB-\frac{A}{B}, not AB\frac{A}{B} and not AA.

Finding intercepts is worth its own line, because it is quick and the test asks often:

  • yy-intercept: set x=0x = 0.
  • xx-intercept: set y=0y = 0.

Q4Medium

Topic: Reading the slope out of standard form

A production constraint is written in the form 3x+4y=123x + 4y = 12, with the two variables on the same side of the equation. What is the slope of the line 3x+4y=123x + 4y = 12?

A) 43- \frac{4}{3}

B) 34\frac{3}{4}

C) 3-3

D) 34- \frac{3}{4}

Show the worked solution

Answer: D

Explanation

Rearrange into y=mx+by = mx + b. Subtract 3x3x from both sides:

4y=3x+124y = -3x + 12

Divide everything by 4:

y=34x+3y = -\frac{3}{4}x + 3

The slope is the number multiplying xx:

m=34m = -\frac{3}{4}

Check the sign by thinking about the picture. When xx grows, 3x3x grows, so 4y4y must shrink to keep the total at 12. The line falls, so the slope is negative ✓

Why each wrong option is wrong:

  • B, 34\frac{3}{4} — the right fraction with the minus dropped. The minus appears when 3x3x moves across the equals sign, and it is the single most common slip in this topic.
  • C, 3-3 — took the coefficient of xx and never divided by 4.
  • A, 43- \frac{4}{3} — inverted the fraction. That is the slope of a perpendicular line, which is the next section, and it is offered here on purpose.

Takeaway: Rearrange into y=mx+by = mx + b rather than guessing from Ax+By=CAx + By = C. If you want the shortcut, the slope is AB-\frac{A}{B} — but rearranging is safer and takes one extra line.


Q5Medium

Topic: The equation of a line through two points

A subscription's total cost was recorded after one month and again after three months, giving the two readings in the table below.

Months elapsed, xx 1 3
Total paid in dollars, yy 4 10

A) 44

B) 11

C) 33

D) 2-2

Show the worked solution

Answer: B

Explanation

Find the slope first:

m=10431=62=3m = \frac{10 - 4}{3 - 1} = \frac{6}{2} = 3

So the line is y=3x+by = 3x + b. Put one of the points in to find bb — use (1,4)(1, 4):

4=3(1)+bb=14 = 3(1) + b \quad\Longrightarrow\quad b = 1

The line is y=3x+1y = 3x + 1, and the yy-intercept is 11.

Check with the other point, which is the whole value of having two: 3(3)+1=103(3) + 1 = 10

Why each wrong option is wrong:

  • A, 44 — read a yy-coordinate straight off one of the given points. The yy-intercept is where the line crosses at x=0x = 0, and neither given point is there.
  • C, 33 — the slope, not the intercept. Both numbers appear in y=3x+1y = 3x + 1; the question asked for the second one.
  • D, 2-2 — substituted the point's coordinates into the wrong slots.

Takeaway: Slope first, then substitute either point to find bb — and check with the other one. Two points give you a free check; use it.


Q6Medium

Topic: Finding an intercept

A supply constraint is graphed in the xyxy-plane as the line 2x5y=202x - 5y = 20. The line crosses the xx-axis at the point (k,0)(k, 0). What is the value of kk?

There are no options — work the answer out and enter it yourself, in the form the grid accepts.

Show the worked solution

Answer: 10

Explanation

Crossing the xx-axis means y=0y = 0 there. That is the whole question — once you know it, the algebra is one line.

Set y=0y = 0:

2x5(0)=202x=20x=102x - 5(0) = 20 \quad\Longrightarrow\quad 2x = 20 \quad\Longrightarrow\quad x = 10

So the line crosses at (10,0)(10, 0), and k=10k = 10.

Check: 2(10)5(0)=202(10) - 5(0) = 20

The pair worth memorising, because it is easy to swap them under pressure:

  • On the xx-axis, y=0y = 0.
  • On the yy-axis, x=0x = 0.

Each axis is where the other coordinate vanishes. If you had set x=0x = 0 here you would have got 5y=20-5y = 20, so y=4y = -4 — a real point on the line, and the wrong one.

This is a grid-in. Enter 10.

Takeaway: To find where a line meets an axis, set the other variable to zero. Say which one out loud before you write, because swapping them gives a plausible wrong answer rather than an obviously wrong one.


Section 3 — Parallel and Perpendicular

Two rules, and the second is the one that gets forgotten.

Lines Their slopes
Parallel equal: m2=m1m_2 = m_1
Perpendicular negative reciprocals: m2=1m1m_2 = -\dfrac{1}{m_1}

"Negative reciprocal" means do two things: flip the fraction over, and change the sign. If one slope is 23\frac{2}{3}, the perpendicular slope is 32-\frac{3}{2}. Doing only one of the two is what the wrong options are made of.

A useful check: two perpendicular slopes always multiply to 1-1. 23×32=1\frac23 \times -\frac32 = -1


Q7Medium

Topic: The slope of a perpendicular line

A surveyor is setting out a path that must meet an existing boundary at a right angle. Line \ell represents that boundary and has equation y=25x+7y = \dfrac{2}{5}x + 7. What is the slope of a line perpendicular to \ell?

A) 25\frac{2}{5}

B) 52\frac{5}{2}

C) 25- \frac{2}{5}

D) 52- \frac{5}{2}

Show the worked solution

Answer: D

Explanation

The slope of \ell is 25\frac{2}{5}. A perpendicular slope is the negative reciprocal — flip it and change its sign:

flip: 52change sign: 52\text{flip: } \frac{5}{2} \qquad \text{change sign: } -\frac{5}{2}

Check with the multiplication test:

25×(52)=1010=1  \frac{2}{5} \times \left(-\frac{5}{2}\right) = -\frac{10}{10} = -1 \; ✓

Why each wrong option is wrong:

  • A, 25\frac{2}{5} — the same slope, which gives a parallel line, not a perpendicular one.
  • B, 52\frac{5}{2} — flipped the fraction and forgot the sign. 25×52=+1\frac25 \times \frac52 = +1, not 1-1.
  • C, 25- \frac{2}{5} — changed the sign and forgot to flip. 25×25=425\frac25 \times -\frac25 = -\frac{4}{25}, not 1-1.

Options B and C are the two halves of the job, offered separately. Doing both is the entire question.

Takeaway: Perpendicular means flip and negate. Multiply the two slopes together as a check — if you do not get exactly 1-1, you have done one half of the job.


Q8Hard

Topic: Parallel lines in standard form

Line pp has equation 4x+3y=94x + 3y = 9. Line qq is parallel to pp and passes through (6,1)(6, -1). What is the yy-intercept of line qq?

A) 9-9

B) 77

C) 33

D) 43- \frac{4}{3}

Show the worked solution

Answer: B

Explanation

Parallel lines have the same slope, so start by finding the slope of pp. Rearrange 4x+3y=94x + 3y = 9:

3y=4x+9y=43x+33y = -4x + 9 \quad\Longrightarrow\quad y = -\frac{4}{3}x + 3

So m=43m = -\frac{4}{3}, and line qq is

y=43x+by = -\frac{4}{3}x + b

Now use the point (6,1)(6, -1) that qq passes through:

1=43(6)+b1=8+bb=7-1 = -\frac{4}{3}(6) + b \quad\Longrightarrow\quad -1 = -8 + b \quad\Longrightarrow\quad b = 7

Check: at x=6x = 6, 43(6)+7=8+7=1-\frac43(6) + 7 = -8 + 7 = -1

Why each wrong option is wrong:

  • A, 9-9 — used +43+\frac43 as the slope, losing the minus sign when rearranging.
  • C, 33 — the yy-intercept of line pp. Parallel lines share a slope, not an intercept; if they shared both they would be the same line.
  • D, 43- \frac{4}{3} — the slope, where the question asked for the intercept.

Takeaway: Parallel means copy the slope, then use the given point to find the new intercept. The old intercept is never the answer — that is what makes the two lines different lines.


Section 4 — Systems of Two Equations

A system is two equations that must both be true at once. Its solution is the point (x,y)(x, y) where the two lines cross.

There are two methods, and it is worth being fluent in both because questions are built to favour one or the other.

Substitution — best when one equation already has a variable alone. Rearrange one equation to "y=y = \ldots", put that into the other, solve, then substitute back.

Elimination — best when the equations are lined up as Ax+By=CAx + By = C. Add or subtract the two equations so that one variable cancels. Multiply one or both equations first if nothing cancels straight away.

Always find both values, and always check both equations. Half the wrong options on system questions are the other variable's value.


Q9Basic

Topic: Solving a system by substitution

Two conditions describe the same pair of quantities at the same moment: the first is y=2x1y = 2x - 1 and the second is 3x+y=143x + y = 14. What is the value of xx?

A) 22

B) 33

C) 55

D) 135\frac{13}{5}

Show the worked solution

Answer: B

Explanation

The first equation already gives yy on its own, so substitute it into the second:

3x+(2x1)=143x + (2x - 1) = 14

Collect:

5x1=145x=15x=35x - 1 = 14 \quad\Longrightarrow\quad 5x = 15 \quad\Longrightarrow\quad x = 3

Then y=2(3)1=5y = 2(3) - 1 = 5, so the crossing point is (3,5)(3, 5).

Check in both equations: y=2(3)1=5y = 2(3) - 1 = 5 ✓ and 3(3)+5=143(3) + 5 = 14

Why each wrong option is wrong:

  • A, 22 — dropped the 1-1 when substituting, solving 5x=105x = 10.
  • C, 55 — the value of yy. Both 3 and 5 come out of this question, and the last line asked for xx.
  • D, 135\frac{13}{5} — moved the 1-1 to the wrong side, solving 5x=135x = 13.

Takeaway: When one equation is already "y=y = \ldots", substitute. Then check in both equations — an answer that satisfies only one of them is not a solution to the system.


Q10Medium

Topic: Solving a system by elimination

A pair of measurements (x,y)(x, y) satisfies both of the conditions {2x+3y=162xy=4\begin{cases} 2x + 3y = 16 \\ 2x - y = 4 \end{cases} at once. What is the value of yy?

A) 2020

B) 72\frac{7}{2}

C) 55

D) 33

Show the worked solution

Answer: D

Explanation

Both equations have 2x2x, so subtracting them removes xx in one step:

(2x+3y)(2xy)=164(2x + 3y) - (2x - y) = 16 - 4

On the left, 2x2x=02x - 2x = 0 and 3y(y)=4y3y - (-y) = 4y:

4y=12y=34y = 12 \quad\Longrightarrow\quad y = 3

Then from the second equation, 2x3=42x - 3 = 4, so 2x=72x = 7 and x=72x = \frac72.

Check both: 2(72)+3(3)=7+9=162(\frac72) + 3(3) = 7 + 9 = 16 ✓ and 2(72)3=42(\frac72) - 3 = 4

The step people get wrong is 3y(y)3y - (-y). Subtracting a negative adds, so it is 4y4y, not 2y2y. Writing the subtraction out with brackets, as above, prevents it.

Why each wrong option is wrong:

  • B, 72\frac{7}{2} — the value of xx. Again, the question named one of the two.
  • C, 55 — added the equations instead of subtracting. That gives 4x+2y=204x + 2y = 20, which eliminates nothing.
  • A, 2020 — a stray total rather than a value of yy; if 4y=124y = 12 then yy is 3, and 20 never enters a correct solution.

Takeaway: Line the equations up and look for a variable with matching coefficients. Same sign, subtract; opposite signs, add. And bracket the second equation before subtracting it, so the double negative does not bite.


Q11Medium

Topic: Building a system from words

At a stall, 3 coffees and 2 teas cost $16, and 1 coffee and 4 teas cost $12. What is the cost, in dollars, of one coffee?

A) 22

B) 145\frac{14}{5}

C) 44

D) 2828

Show the worked solution

Answer: C

Explanation

Let cc be the price of a coffee and tt the price of a tea. The two sentences become two equations:

3c+2t=16c+4t=123c + 2t = 16 \qquad c + 4t = 12

Eliminate tt. Multiply the first equation by 2 so both have 4t4t:

6c+4t=326c + 4t = 32

Now subtract the second equation:

(6c+4t)(c+4t)=32125c=20c=4(6c + 4t) - (c + 4t) = 32 - 12 \quad\Longrightarrow\quad 5c = 20 \quad\Longrightarrow\quad c = 4

Then 4+4t=124 + 4t = 12, so t=2t = 2.

Check both sentences in words: 3 coffees and 2 teas is 12+4=1612 + 4 = 16 ✓, and 1 coffee and 4 teas is 4+8=124 + 8 = 12

Why each wrong option is wrong:

  • A, 22 — the price of a tea. Define your letters in writing before you start; it is the cheapest insurance on the test.
  • B, 145\frac{14}{5} — divided all the money, $28, by all the drinks, 10, giving an average price per drink. That would be the answer only if coffee and tea cost the same, and the question exists because they do not.
  • D, 2828 — added the two totals. That is the cost of everything on both orders, not the cost of one coffee.

Takeaway: Write down what each letter means before writing equations, and answer in those terms at the end. Then read both original sentences back with your numbers in them.


Q12Hard

Topic: A system with no solution

The system {6x2y=109x+ky=3\begin{cases} 6x - 2y = 10 \\ 9x + ky = 3 \end{cases}, in which kk is a constant, has no solution. What is the value of kk?

A) 3-3

B) 33

C) 43- \frac{4}{3}

D) 2-2

Show the worked solution

Answer: A

Explanation

Two lines fail to have a crossing point exactly when they are parallel — same slope, different intercept. So put both into y=mx+by = mx + b form.

First equation:

6x2y=102y=6x+10y=3x56x - 2y = 10 \quad\Longrightarrow\quad -2y = -6x + 10 \quad\Longrightarrow\quad y = 3x - 5

Slope 3, intercept 5-5.

Second equation, keeping kk:

9x+ky=3ky=9x+3y=9kx+3k9x + ky = 3 \quad\Longrightarrow\quad ky = -9x + 3 \quad\Longrightarrow\quad y = -\frac{9}{k}x + \frac{3}{k}

For the slopes to match:

9k=39=3kk=3-\frac{9}{k} = 3 \quad\Longrightarrow\quad -9 = 3k \quad\Longrightarrow\quad k = -3

Now confirm it is really "no solution" and not "infinitely many". With k=3k = -3 the second line is y=3x1y = 3x - 1. Same slope as y=3x5y = 3x - 5, different intercept — so the lines are parallel and never meet ✓

That last check matters. Matching the slopes is only half the condition; if the intercepts had matched too, the two equations would describe the same line and the system would have infinitely many solutions instead.

Why each wrong option is wrong:

  • B, 33 — matched 9k=3\frac9k = 3 and lost the minus sign that comes from moving 9x9x across.
  • C, 43- \frac{4}{3} — divided the wrong pair of coefficients.
  • D, 2-2 — copied the 2-2 out of the first equation. The coefficients do have to be proportional, but 696 \to 9 is a factor of 32\frac32, so 2-2 would have to become 3-3.

Takeaway: No solution means parallel: equal slopes, different intercepts. Infinitely many means the same line: equal slopes and equal intercepts. Always check the intercept after matching the slope — that is what separates the two cases.


Q13Medium

Topic: Infinitely many solutions

The system {4x+6y=142x+3y=c\begin{cases} 4x + 6y = 14 \\ 2x + 3y = c \end{cases}, in which cc is a constant, has infinitely many solutions. What is the value of cc?

There are no options — work the answer out and enter it yourself, in the form the grid accepts.

Show the worked solution

Answer: 7

Explanation

Infinitely many solutions means the two equations describe the same line — every point on it solves both.

Look at the left-hand sides. 4x+6y4x + 6y is exactly twice 2x+3y2x + 3y. So the first equation is the second one doubled, and for them to be the same line the right-hand sides must be in that same ratio:

14=2cc=714 = 2c \quad\Longrightarrow\quad c = 7

Check by halving the first equation throughout:

4x+6y=142x+3y=74x + 6y = 14 \quad\Longrightarrow\quad 2x + 3y = 7

which is precisely the second equation with c=7c = 7

Contrast this with Q12. There the coefficients were proportional but the constants were not, giving parallel lines and no solution. Here everything is in the same ratio, so it is one line drawn twice.

This is a grid-in. Enter 7.

Takeaway: Infinitely many solutions means one equation is a multiple of the other — coefficients and constant, all scaled by the same factor. Find the factor from the xx terms, then apply it to the constant.


Q14Medium

Topic: What the solution of a system means on a graph

Two lines are graphed in the xyxy-plane and intersect at the point (4,2)(4, -2). Which of the following must be true?

A) Both lines have a slope of 4

B) x=4x = 4 and y=2y = -2 satisfy both equations

C) Both lines pass through the origin

D) The two lines have the same yy-intercept

Show the worked solution

Answer: B

Explanation

The point where two lines cross is the point that lies on both of them. So its coordinates satisfy both equations at once — and that is exactly what "the solution of the system" means.

So x=4x = 4 and y=2y = -2 make both equations true. That is the whole content of an intersection point, and nothing else is forced.

To see that nothing else follows, here are two actual lines meeting at (4,2)(4, -2):

y=x6andy=x+2y = x - 6 \qquad\text{and}\qquad y = -x + 2

Check: at x=4x = 4 the first gives 46=24 - 6 = -2 ✓ and the second gives 4+2=2-4 + 2 = -2 ✓ They do cross there. Now test the other options against them.

Why each wrong option is wrong:

  • A, "Both lines have a slope of 4" — the example lines have slopes 1 and 1-1. The 4 is an xx-coordinate, not a slope. Two lines that cross must have different slopes, so they certainly cannot both be 4.
  • C, "Both lines pass through the origin" — the example lines cross the yy-axis at 6-6 and 22. If both lines went through the origin they would cross there, not at (4,2)(4, -2).
  • D, "The two lines have the same yy-intercept" — again 6-6 and 22. Two distinct lines meet at only one point; if they shared a yy-intercept they would meet on the yy-axis.

Takeaway: The solution of a system is the intersection point, and it means one thing only: those coordinates satisfy both equations. When a question asks what must be true, try to build an example that breaks each option — one counterexample is enough to eliminate it.


Section 5 — Reading a Linear Model

The SAT dresses slope and intercept up as a story and asks what one of the numbers means. The answer is always about units.

In y=mx+by = mx + b describing a real situation:

  • bb is the value at the start, when x=0x = 0. Its units are the units of yy.
  • mm is how fast yy changes per unit of xx. Its units are yy-units per xx-unit.

That unit test settles most of these questions on its own. If the model is dollars against hours, a rate must be dollars per hour, so any option measured in plain dollars or plain hours is out before you think about the story.


Q15Medium

Topic: Interpreting the intercept

A gym advertises its membership with the formula C=30+12wC = 30 + 12w, where CC is the total cost in dollars and ww is the number of weeks a member stays. A prospective member wants to know what the two numbers in the formula stand for. What does the 30 represent?

A) The cost of each week of membership

B) The number of weeks in the membership

C) A one-off joining fee, charged before any weeks

D) The total cost of a 30-week membership

Show the worked solution

Answer: C

Explanation

Set w=0w = 0 — no weeks used yet:

C=30+12(0)=30C = 30 + 12(0) = 30

So $30 is owed before any weeks are counted. That is a joining fee.

A is what the 12 means: each extra week adds $12, since C(w+1)C(w)=12C(w+1) - C(w) = 12. B confuses a cost with a count — the 30 is in dollars. D would be 30+12(30)=39030 + 12(30) = 390.

Takeaway: Substitute x=0x = 0 to see what the constant means, and check the units. A dollar amount cannot be a number of weeks.


Q16Medium

Topic: Interpreting the slope with units

The number of bacteria in a culture is modelled by P=500+80hP = 500 + 80h, where hh is hours since the start. Which statement is best supported by the model?

A) The population increases by 80 each hour

B) The population increases by 500 each hour

C) The population doubles every 80 hours

D) There were 80 bacteria at the start

Show the worked solution

Answer: A

Explanation

The number multiplied by hh is the rate. Between any hour and the next:

P(h+1)P(h)=80P(h+1) - P(h) = 80

So the population rises by 80 each hour, and it starts at 500.

B swaps the two numbers. C describes exponential growth, which this model is not — a linear model adds a fixed amount, it does not multiply. (After 80 hours the population is 500+6400=6900500 + 6400 = 6900, which is far more than double.) D reads the rate as the starting value.

Takeaway: Linear means adds the same amount each step. "Doubles every" is exponential and belongs to a different kind of model entirely — Chapter 5.


Section 6 — Mixed Practice

Slopes, forms, parallels and systems, shuffled.


Q17Basic

Topic: Slope between two points with negatives

Two readings taken during a cooling experiment were recorded in the table below.

xx 2-2 3
yy 7 3-3

What is the slope of the line through those two points?

A) 22

B) 12- \frac{1}{2}

C) 45\frac{4}{5}

D) 2-2

Show the worked solution

Answer: D

Explanation

m=373(2)=105=2m = \frac{-3 - 7}{3 - (-2)} = \frac{-10}{5} = -2

The line falls from y=7y = 7 to y=3y = -3, so a negative slope is right ✓

A has the sign flipped. B is upside down. C added the yy values.

Takeaway: Subtracting a negative adds: 3(2)=53 - (-2) = 5. Then sanity-check the sign against whether the line rises or falls.


Q18Medium

Topic: Perpendicular slope from standard form

A new access road must cross an existing pipeline at a right angle. The pipeline is modelled by line \ell, whose equation is 2x5y=152x - 5y = 15. What is the slope of a line perpendicular to \ell?

A) 52\frac{5}{2}

B) 52- \frac{5}{2}

C) 25\frac{2}{5}

D) 25- \frac{2}{5}

Show the worked solution

Answer: B

Explanation

Rearrange: 5y=2x+15-5y = -2x + 15, so y=25x3y = \frac{2}{5}x - 3 and m=25m = \frac25.

Perpendicular means flip and negate: 52-\frac52. Check: 25×52=1\frac25 \times -\frac52 = -1

A flipped only. C is the parallel slope. D negated only.

Takeaway: Rearrange to y=mx+by = mx + b first, then do both halves of "negative reciprocal" and confirm the product is 1-1.


Q19Medium

Topic: A system solved by elimination with scaling

Two orders placed with the same supplier satisfy 3x+2y=193x + 2y = 19 and 5x2y=135x - 2y = 13, where xx and yy are the quantities of two items. What is the value of xx?

There are no options — work the answer out and enter it yourself, in the form the grid accepts.

Show the worked solution

Answer: 4

Explanation

The yy terms are +2y+2y and 2y-2y — opposite signs, so adding the equations cancels them:

(3x+2y)+(5x2y)=19+138x=32x=4(3x + 2y) + (5x - 2y) = 19 + 13 \quad\Longrightarrow\quad 8x = 32 \quad\Longrightarrow\quad x = 4

Then 3(4)+2y=193(4) + 2y = 19 gives 2y=72y = 7, so y=72y = \frac72.

Check both: 12+7=1912 + 7 = 19 ✓ and 207=1320 - 7 = 13

This is a grid-in. Enter 4.

Takeaway: Opposite signs on a variable, add the equations. Matching signs, subtract. Spotting which before you start saves the whole scaling step.


Q20Medium

Topic: The equation of a line from a graph description

A line on a scale drawing falls at a steady rate, dropping one unit for every two units travelled across. The line is known to pass through the point (6,1)(6, 1). What is its yy-intercept?

A) 11

B) 2-2

C) 44

D) 77

Show the worked solution

Answer: C

Explanation

y=12x+b1=12(6)+b=3+bb=4y = -\tfrac12 x + b \quad\Longrightarrow\quad 1 = -\tfrac12(6) + b = -3 + b \quad\Longrightarrow\quad b = 4

Check: at x=6x = 6, 12(6)+4=3+4=1-\frac12(6) + 4 = -3 + 4 = 1

A used the point's yy-coordinate. B lost the minus on the slope. D added the coordinates together.

Takeaway: Substitute the point into y=mx+by = mx + b and solve for bb. Carry the minus sign through the multiplication before doing anything else.


Q21Hard

Topic: Comparing two linear models

Two printing firms quote for nn copies. Firm A charges C=40+0.20nC = 40 + 0.20n and firm B charges C=10+0.35nC = 10 + 0.35n. For how many copies do the two firms charge the same amount?

There are no options — work the answer out and enter it yourself, in the form the grid accepts.

Show the worked solution

Answer: 200

Explanation

"Charge the same" means the two expressions are equal — the point where the two lines cross:

40+0.20n=10+0.35n40 + 0.20n = 10 + 0.35n

Gather the nn terms on the side that keeps them positive, by subtracting 0.20n0.20n:

40=10+0.15n40 = 10 + 0.15n

Subtract 10:

30=0.15nn=300.15=20030 = 0.15n \quad\Longrightarrow\quad n = \frac{30}{0.15} = 200

Check both quotes at 200 copies: firm A charges 40+40=8040 + 40 = 80, firm B charges 10+70=8010 + 70 = 80

Worth noticing which firm is cheaper on each side, because the test often asks that as a follow-up. Firm B starts cheaper (a $10 setup against $40) but charges more per copy, so it wins on small orders and loses on large ones. At 100 copies B costs $45 against A's $60; at 300 copies A costs $100 against B's $115.

This is a grid-in. Enter 200.

Takeaway: "The same cost", "break even", "when are they equal" all mean set the two expressions equal to each other. The one with the bigger rate always wins eventually; the crossing point is where the lead changes hands.


Q22Hard

Topic: A system needing both equations scaled

Two conditions on the same pair of quantities are recorded as 2x+5y=242x + 5y = 24 and 3x2y=23x - 2y = -2. What is the value of yy?

A) 22

B) 7676

C) 44

D) 2-2

Show the worked solution

Answer: C

Explanation

Nothing cancels as the equations stand, so scale them until something does. To clear xx, make both xx terms 6x6x — multiply the first by 3 and the second by 2:

6x+15y=726x4y=46x + 15y = 72 \qquad 6x - 4y = -4

Multiply every term, including the right-hand sides: 3×24=723 \times 24 = 72 and 2×(2)=42 \times (-2) = -4. Forgetting the right-hand side is the usual way this goes wrong.

Now subtract the second from the first. Bracket it, so the double negative is visible:

(6x+15y)(6x4y)=72(4)(6x + 15y) - (6x - 4y) = 72 - (-4)

19y=76y=419y = 76 \quad\Longrightarrow\quad y = 4

Then 2x+5(4)=242x + 5(4) = 24 gives 2x=42x = 4, so x=2x = 2.

Check both original equations: 2(2)+5(4)=4+20=242(2) + 5(4) = 4 + 20 = 24 ✓ and 3(2)2(4)=68=23(2) - 2(4) = 6 - 8 = -2

Why each wrong option is wrong:

  • A, 22 — the value of xx. Both 2 and 4 fall out of this question, and the last line named yy.
  • B, 7676 — reached 19y=7619y = 76 and wrote 76 down. The unfinished last step.
  • D, 2-2 — copied the constant from the second equation.

Takeaway: Scale until one variable's coefficients match, multiplying every term including the constant. Same sign, subtract; opposite signs, add. Then find the second variable and check both original equations.


Q23Medium

Topic: A parallel line through a given point

A second road is to run parallel to an existing one, which is modelled by y=3x2y = 3x - 2. The new road passes through the point (2,11)(2, 11). What is the yy-intercept of the new road?

A) 55

B) 2-2

C) 1111

D) 1717

Show the worked solution

Answer: A

Explanation

Parallel means the same slope, 3, so the new line is y=3x+by = 3x + b. Substitute (2,11)(2, 11):

11=3(2)+b=6+bb=511 = 3(2) + b = 6 + b \quad\Longrightarrow\quad b = 5

Check: at x=2x = 2, 3(2)+5=113(2) + 5 = 11

B is the original line's intercept — parallel lines share a slope, never an intercept. C is the point's yy-value. D added the 6 instead of subtracting it.

Takeaway: Copy the slope, substitute the point, solve for bb. If you get the original intercept back, you have written down the same line.


Q24Medium

Topic: A perpendicular line through a given point

A cable is to be strung perpendicular to an existing line modelled by y=2x+1y = -2x + 1, and it must pass through the anchor point (4,3)(4, 3). What is the yy-intercept of the new line?

A) 11

B) 1111

C) 12\frac{1}{2}

D) 2-2

Show the worked solution

Answer: A

Explanation

The given slope is 2-2, which is 21-\frac21. Flip and negate: m=12m = \frac12. Check: 2×12=1-2 \times \frac12 = -1

So the line is y=12x+by = \frac12 x + b. Substitute (4,3)(4, 3):

3=12(4)+b=2+bb=13 = \tfrac12(4) + b = 2 + b \quad\Longrightarrow\quad b = 1

B used 2-2 as the new slope, so it built a parallel line. C gives the slope. D gives the original slope.

Takeaway: A whole number 2-2 is the fraction 21-\frac21; flipping it gives 12\frac12. Writing the whole number as a fraction first makes the flip obvious.


Q25Basic

Topic: Finding an xx-intercept

A constraint is graphed in the xyxy-plane as the line 5x+2y=305x + 2y = 30. The graph crosses the xx-axis at the moment the second quantity reaches zero. At what value of xx does the graph cross the xx-axis?

There are no options — work the answer out and enter it yourself, in the form the grid accepts.

Show the worked solution

Answer: 6

Explanation

On the xx-axis, y=0y = 0:

5x+2(0)=305x=30x=65x + 2(0) = 30 \quad\Longrightarrow\quad 5x = 30 \quad\Longrightarrow\quad x = 6

Check: 5(6)+0=305(6) + 0 = 30

Setting x=0x = 0 instead would give y=15y = 15 — a real point on the line, and the answer to the other question.

This is a grid-in. Enter 6.

Takeaway: xx-axis means y=0y = 0. Each axis is where the other coordinate is zero.


Q26Hard

Topic: A system from a ticket problem

A theatre sold a total of 250 tickets for one performance and took $2400 at the box office. Adult tickets were priced at $12 each and child tickets at $7 each, and every ticket sold was one or the other. How many adult tickets were sold?

A) 120120

B) 130130

C) 250250

D) 200200

Show the worked solution

Answer: B

Explanation

Let aa be adult tickets and cc child tickets. Two facts, two equations:

a+c=25012a+7c=2400a + c = 250 \qquad 12a + 7c = 2400

Substitute c=250ac = 250 - a into the money equation:

12a+7(250a)=240012a + 7(250 - a) = 2400

12a+17507a=24005a=650a=13012a + 1750 - 7a = 2400 \quad\Longrightarrow\quad 5a = 650 \quad\Longrightarrow\quad a = 130

So 130 adult and 120 child tickets. Check: 130+120=250130 + 120 = 250 ✓ and 12(130)+7(120)=1560+840=240012(130) + 7(120) = 1560 + 840 = 2400

A is the child count — both numbers come out, and the question named adults. C is the total. D assumed every ticket was an adult ticket.

Takeaway: Two unknowns need two equations: one counting the items, one counting the money. Then check both, and read which of the two the question wanted.


Q27Medium

Topic: A linear function given at two inputs

A quantity changes at a constant rate, so it is modelled by a linear function ff. Two of its values were recorded in the table below.

xx 2 6
f(x)f(x) 5 13

The starting value of the model is the value of the function at an input of zero. What is f(0)f(0)?

A) 11

B) 55

C) 22

D) 99

Show the worked solution

Answer: A

Explanation

"Linear" means constant slope, so treat f(2)=5f(2) = 5 and f(6)=13f(6) = 13 as the points (2,5)(2, 5) and (6,13)(6, 13):

m=13562=84=2m = \frac{13 - 5}{6 - 2} = \frac{8}{4} = 2

So f(x)=2x+bf(x) = 2x + b, and 5=2(2)+b5 = 2(2) + b gives b=1b = 1. Since f(0)f(0) is the yy-intercept, f(0)=1f(0) = 1.

Check with the other point: f(6)=2(6)+1=13f(6) = 2(6) + 1 = 13

There is a quicker way. Going from x=2x = 2 down to x=0x = 0 is two steps back, and each step is worth 2, so f(0)=52(2)=1f(0) = 5 - 2(2) = 1.

B is f(2)f(2). C is the slope. D averaged the two given outputs, which would be f(4)f(4), not f(0)f(0).

Takeaway: f(0)f(0) is the yy-intercept. With a linear function you can walk backwards from a known point in steps of the slope — often faster than solving for bb.


Q28Medium

Topic: Testing whether a point is on a line

A constraint on two quantities is graphed as the line 3x4y=123x - 4y = 12. Which of the following points lies on the line 3x4y=123x - 4y = 12?

A) (0, 3)\left( 0, \ 3\right)

B) (8, 3)\left( 8, \ 3\right)

C) (4, 3)\left( 4, \ 3\right)

D) (3, 8)\left( 3, \ 8\right)

Show the worked solution

Answer: B

Explanation

There is nothing to solve. Substitute each point and see which one works — and with a calculator available this takes seconds.

A 3(0)4(3)=12no\textbf{A } 3(0) - 4(3) = -12 \quad \text{no} B 3(8)4(3)=2412=12\textbf{B } 3(8) - 4(3) = 24 - 12 = 12 \quad ✓ C 3(4)4(3)=1212=0no\textbf{C } 3(4) - 4(3) = 12 - 12 = 0 \quad \text{no} D 3(3)4(8)=932=23no\textbf{D } 3(3) - 4(8) = 9 - 32 = -23 \quad \text{no}

Option D is worth a second look: it is B's coordinates swapped. The order of a coordinate pair is (x,y)(x, y), always, and a question offering both orders is checking that you know which is which.

Takeaway: "Which point lies on..." is a substitution question, not a solving question. Test the options; it is faster and it cannot go wrong.


Q29Medium

Topic: Finding a missing coordinate from a slope

A line drawn through the points (1,2)(1, 2) and (5,k)(5, k) is known to rise three units for every one unit it runs. The second coordinate of the second point has been lost. What is the value of kk?

There are no options — work the answer out and enter it yourself, in the form the grid accepts.

Show the worked solution

Answer: 14

Explanation

Put the two points into the slope formula and set it equal to 3:

k251=3k24=3\frac{k - 2}{5 - 1} = 3 \quad\Longrightarrow\quad \frac{k - 2}{4} = 3

Multiply both sides by 4:

k2=12k=14k - 2 = 12 \quad\Longrightarrow\quad k = 14

Check: 14251=124=3\frac{14 - 2}{5 - 1} = \frac{12}{4} = 3

Or walk it: from x=1x = 1 to x=5x = 5 is 4 steps, each worth 3, so yy climbs by 12, from 2 to 14.

This is a grid-in. Enter 14.

Takeaway: A missing coordinate with a known slope is one equation. Set the slope formula equal to the given slope and solve — or count the steps and multiply.


Q30Hard

Topic: Finding a coefficient from a required slope

In the equation 4x+ay=84x + ay = 8, the letter aa is a constant chosen so that the graph has a particular steepness. The graph is required to have slope 2-2. What is the value of aa?

A) 22

B) 2-2

C) 88

D) 12\frac{1}{2}

Show the worked solution

Answer: A

Explanation

Rearrange, keeping aa as a letter:

ay=4x+8y=4ax+8aay = -4x + 8 \quad\Longrightarrow\quad y = -\frac{4}{a}x + \frac{8}{a}

The slope is 4a-\frac{4}{a}, and it has to be 2-2:

4a=24=2aa=2-\frac{4}{a} = -2 \quad\Longrightarrow\quad 4 = 2a \quad\Longrightarrow\quad a = 2

Check by substituting back: 4x+2y=84x + 2y = 8 becomes y=2x+4y = -2x + 4, slope 2-2

B copied the slope itself. C read the 8. D inverted the relationship, giving a=12a = \frac12, which would make the slope 8-8.

Takeaway: Rearrange with the unknown constant still in place, then set the slope expression equal to the required value. Always substitute back — it costs one line and catches an inverted fraction immediately.


Q31Medium

Topic: A system with no solution, recognised quickly

Which of the following systems has no solution?

A) y=2x+1y = 2x + 1 and y=3x+1y = 3x + 1

B) y=2x+1y = 2x + 1 and y=2x+1y = 2x + 1

C) y=2x+1y = 2x + 1 and y=2x4y = 2x - 4

D) y=2x+1y = 2x + 1 and y=2x+1y = -2x + 1

Show the worked solution

Answer: C

Explanation

No solution means the lines are parallel but not identical — same slope, different intercept. Both equations are already in y=mx+by = mx + b form, so read them off:

Option Slopes Intercepts Result
A 2 and 3 1 and 1 different slopes → they cross once
B 2 and 2 1 and 1 the same line → infinitely many
C 2 and 2 1 and 4-4 parallel, distinct → none
D 2 and 2-2 1 and 1 different slopes → they cross once

Only C has matching slopes with different intercepts.

Option B is the one to be careful with: identical equations look like they should be a special case of "no solution", and they are the opposite — every point on the line solves both.

Takeaway: Compare slopes first. Different slopes always cross. Same slope splits into two cases, and it is the intercept that decides which: same intercept means infinitely many, different means none.


Q32Medium

Topic: Which line is steeper

Four lines are described below, some by an equation and some by two points they pass through. Which of the four has the greatest slope?

A) y=5x+2y = -5x + 2

B) the line through (0,0)(0, 0) and (4,8)(4, 8)

C) 3xy=13x - y = 1

D) the line through (1,1)(1, 1) and (3,9)(3, 9)

Show the worked solution

Answer: D

Explanation

Work out all four slopes and compare.

A m=5B m=8040=2\textbf{A } m = -5 \qquad \textbf{B } m = \frac{8 - 0}{4 - 0} = 2 C 3xy=1y=3x1,  m=3D m=9131=82=4\textbf{C } 3x - y = 1 \Rightarrow y = 3x - 1,\; m = 3 \qquad \textbf{D } m = \frac{9 - 1}{3 - 1} = \frac{8}{2} = 4

The greatest is 4, option D.

The trap is option A. Its slope has the largest size, and 5-5 is the smallest of the four numbers. "Greatest slope" means greatest value, so a negative slope can never win — unless every option is negative.

Takeaway: Convert everything to a single number, then compare as numbers. "Greatest slope" is not "steepest"; a slope of 5-5 is steeper than 4 but far smaller.